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makkiz [27]
3 years ago
13

Please help me with this answer correct

Chemistry
2 answers:
IRINA_888 [86]3 years ago
8 0
Trust in God and he will guide you throughout life, trust me without God life sucks and is meaningless! Jesus was there for you when other hurt and abandoned you he was with you comforting you, don’t neglect him trust and love him! Repent of your sins and live by the Bible!
oksano4ka [1.4K]3 years ago
5 0

Answer:

hope this helps :)

Explanation:

for the first one, you can look at the periodic table and look at the atomic number and it will show you how many protons there are giving you the answer because protons and electrons are equal in a pure element

a- carbon

b- neon

c- boron

d- oxygen

e- helium

f- hydrogen

g- lithium

h- beryllium

i- nitrogen

1- sulfur

2- S

3- 16

4- 32.066

5- 16

6- 16

7- 16.066

8- draw circles and put 16 dots like on the other page and in the middle put 16 nuetrons and electrons

9- 6 i think

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Describe the process used to measure out a specific mass of a solid.
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You first weigh you're solid to determine it's mass. Then put it in a container that has liquid with definite volume which can't dissolve solid, absolutely when you put solid in liquid, liquid raise and you have volume of solid. <span><span>
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6 0
3 years ago
Suppose that 3.33 g of acetone at 25.0 °C condenses on the surface of a 44.0-g block of aluminum that is initially at 25 °C. If
jeyben [28]

Answer:

68.6 °C

Explanation:

From conservation of energy, the heat lost by acetone, Q = heat gained by aluminum, Q'

Q = Q'

Q = mL where Q = latent heat of vaporization of acetone, m = mass of acetone = 3.33 g and L = specific latent heat of vaporization of acetone = 518 J/g

Q' = m'c(θ₂ - θ₁) where m' = mass of aluminum = 44.0 g, c = specific heat capacity of aluminum = 0.9 J/g°C, θ₁ = initial temperature of aluminum = 25°C and θ₂ = final temperature of aluminum = unknown

So, mL = m'c(θ₂ - θ₁)

θ₂ - θ₁ = mL/m'c

θ₂ = mL/m'c + θ₁

substituting the values of the variables into the equation, we have

θ₂ = 3.33 g × 518 J/g/(44.0 g × 0.9 J/g°C) + 25 °C

θ₂ = 1724.94 J/(39.6 J/°C) + 25 °C

θ₂ = 43.56 °C + 25 °C

θ₂ = 68.56 °C

θ₂ ≅ 68.6 °C

So, the final temperature (in °C) of the metal block is 68.6 °C.

5 0
3 years ago
A sample of cobalt has a mass of 27 g and a density of 9 g/cm^3. What would be its volume?
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Given ,

Mass of sample of cobalt = 27 g

density of sample of cobalt = 9g/cm^3

We know that ,

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We can deduce the following as

Volume = mass of sample/density of sample

Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3

The volume is \fbox{3cm cube}
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3 years ago
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