Answer:
6.48L
Explanation:
Given parameters:
V₁ = 2.5L
P₁ = 105 kPa
P₂ = 40.5 kPa
Condition: constant temperature
Unknown:
V₂ = ?
Solution:
To solve this problem, we are considering pressure and volume relationship. This should be solved by applying the knowledge of Boyle's law.
The law states that "The volume of fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁V₁ = P₂V₂
where P and V are pressure and volume, 1 and 2 represents initial and final states.
Substitute to find the V₂;
105 x 2.5 = 40.5 x V₂
Solving for V₂ gives 6.48L
Answer: I NEED POINTS!!!!
Explanation:
Answer:
<em>The correct option is the structure in the option D. </em>
Explanation:
Ammonia contains a single nitrogen atom bonded to three hydrogen atoms.
The structure present in option A shows a single nitrogen atom bonded with a single hydrogen atom hence it is not correct.
The structure in option B shows a nitrogen atom bonded to four hydrogen atoms hence it is also not correct.
The structure in option C shows a nitrogen atom bonded to two hydrogen atoms hence it is also not correct.
The structure in option D shows a nitrogen atom bonded to three hydrogen atoms which is the correct structure of ammonia (NH3).
Answer:
V₂ = 123.6 L
Explanation:
According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,
P₁ V₁ = P₂ V₂ ----- (1)
Data Given;
P₁ = 103 kPa
V₁ = 30 L
P₂ = 25 kPa
V₂ = ?
Solution:
Solving equation 1 for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (103 kPa × 30 L) ÷ 25 kPa
V₂ = 123.6 L
Result:
As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
