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Harlamova29_29 [7]
3 years ago
6

A gas occupies a volume of 50.0 mL at 100K and 630 mmHg. At what temperature would

Chemistry
1 answer:
rodikova [14]3 years ago
3 0
PV / T = P'V' / T'

V = V'

P / T = P' / T'

P = 630 mmHg
T = 100 K
P' = 1760 mmHg
T' = ?

630 / 100 = 1760 / T'

T' = 1760 / 6,3

T' = 279,36 K

T' ≈ 280 K
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Hitman42 [59]

Answer:

x=2.8moles

Explanation:

first step balance the chemical equation

C2H6+O2-->CO2+2H2O

use more ratio to find the moles of water

1mole of C2H6= 2 moles of H2O

1.4mole of C2H6=?x

cross multiply

x=2.8 moles of H2O

4 0
3 years ago
Fluorine gas reacts with aqueous iron (II) iodine to produce iron (II) fluoride and iodine liquid What is the balanced chemical
Andru [333]

Answer:

F₂ (g) + FeI₂ (aq) →  FeF₂ (aq) +  I₂ (l)

Explanation:

Our reactants are:

F₂ → Fluorine gas, a dyatomic molecule

FeI₂ → Iron (II) iodine

Our products are:

I₂ → Iodine

FeF₂ → Iron (II) fluoride

Then, the reaction is:

F₂ (g) + FeI₂ (aq) →  FeF₂ (aq) +  I₂ (l)

We see it is completely balanced.

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4.60 mL of 0.1852 M HNO3 is titrated to the phenolphthalein indicator endpoint with 27.35 mL of a KOH solution. What is the mola
Kamila [148]

Answer:

M_{base}=0.0311M

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

n_{acid}=n_{base}

Which in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the base (KOH) to obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M

Regards!

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3 years ago
How would i calculate molecules of water produced in a reaction?
levacccp [35]
You would calculate them by dividing them and then multiplying to get the final answer
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