I would expect it to be a gas, because both hydrogen and chlorine are gases at room temperature. The actual answer is a gas, you can read up on it here: https://global.britannica.com/science/hydrogen-chloride.
Hope it helps.
The molecular formula is C₄H₈O.
We must <em>calculate the masses</em> of C, H, and O from the masses given.
Mass of C = 17.873 mg CO₂ × (12.01 mg C/44.01 mg CO₂) = 4.8774 mg C
Mass of H = 7.316 mg H₂O × (2.016 mg H/18.02 mg H₂O) = 0.818 48 mg H
Mass of O = Mass of compound - Mass of C - Mass of H
= (7.321 – 4.8774 – 0.818 48) mg = 1.6251 mg
Now, we must convert these <em>masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u> </u><em><u>m</u></em><u>/mg </u> <em><u>n</u></em><u>/mmol</u> <u> Ratio </u> <u>Integers</u>
C 4.877 4 0.406 11 3.9984 4
H 0.818 48 0.811 99 7.9944 8
O 1.625 1 0.101 57 1 1
The empirical formula is C₄H₈O.
Answer:
51.8 L is the new volume
Explanation:
In the two situations we have this relationship:
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂
Let's convert the temperature to absolute values
T°K = T°C + 273
22.9°C + 273 = 295.9 K
44.5°C + 273 = 317.5 K
Let's convert now, the Torr to atm.
778 Torr . 1 atm / 760 Torr = 1.02 atm
Now we can replace:
3.4 atm . 14.5L / 295.9K = 1.02 atm . V₂ / 317K
(3.4 atm . 14.5L / 295.9K) . 317 K = 1.02 atm . V₂
( (3.4 atm . 14.5L / 295.9K) . 317 K ) / 1.02 atm = V₂ → 51.8 L
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂ is derived from the Ideal Gases Law equation, and it is fulfilled when the moles of a gas, remains constant after the change of T°, pressure and volume.