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777dan777 [17]
3 years ago
5

Identify the element in C6H12O6 that allows it to be classified as an organic compound.

Chemistry
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

i dont know lol

Explanation:

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The enthalpy of combustion of n-octane, C8H18, is –4.79 × 107 J/kg. What is the enthalpy of combustion expressed in kJ/g?
SIZIF [17.4K]

Answer:

47,9 kJ/g

Explanation:

The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:

-4,79x10^7J/kg \frac{1kJ}{1000J} \frac{1kg}{1000g} = <em>47,9kJ/g</em>

<em></em>

I hope it helps!

6 0
4 years ago
Positrons cannot penetrate matter more than a few atomic diameters, but positron emission of radiotracers can be monitored in me
Elina [12.6K]

When a nuclide's nucleus contains more protons than neutrons, a positron is created, whereas radionuclides are utilized to emit both a positron and a neutrino.

<h3></h3><h3>What exactly does positron emission tomography entail?</h3>

In the field of medical diagnostics, it is simple to monitor the positron emission of radiotracers. Positron-emission tomography, also known as PET scans, is frequently used to examine the structure and function of the brain. When an isotope annihilates an electron, positrons are released, which are used in positron-emission tomography. As a result, alpha photons are released that are 180 degrees apart from one another. The devices can now identify these protons, and they can also evaluate photos. A positron emission tomography (PET) scan is an imaging procedure that can help show how your tissues and organs' metabolisms or biochemical processes work. In order to display both typical and abnormal metabolic activity, the PET scan uses a radioactive substance (tracer).

To learn more about Positron-emission tomography, click below

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3 0
1 year ago
You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
Nataly [62]
First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

                                                                =  0.15 mol

then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

                                                      =   0.12 M

Total volume = 0.5 L + 0.02 L= 0.52 L

∴[acetic acid] = moles acetic acid after adding OH- / total volume

                        = 0.13mol / 0.52L

                       = 0.25 M

and [acetate ) = 0.12 mol / 0.52L
 
                        = 0.23 M

by using H-H equation we can get PH:

PH = Pka + ㏒[salt/acid]

when we have Ka = 1.8 x 10^-5

∴Pka = -㏒Ka 

        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

        = 4.66
6 0
3 years ago
Please help please help
otez555 [7]

Answer:

The mass percentage of chlorine is 60.66 % chlorine in the compound sodium chloride.

Explanation:

3 0
3 years ago
Please help me out with this assignment
liberstina [14]

Answer:

1. 7 meters

2. gullet

4. Not sure about this

6. strong

7. digestive

8. starch

12. Not sure about this either

14. Water

15. Jejunum

19. teeth

Hope this helps!

8 0
4 years ago
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