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tangare [24]
3 years ago
7

10 POINTS ANSWER FAST!

Physics
2 answers:
Andreyy893 years ago
7 0

Answer:

indeed relative

Explanation:

olga2289 [7]3 years ago
5 0

If you look closely at the question it's pretty easy but since I know what your here for the answer is indeed relative

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What is the kinetic energy of a golf ball with a mass of 0.046 kg traveling at 15.5<br> m/s?
Serjik [45]

Answer:

<h2>5.53 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 0.046 \times {15.5}^{2}  \\  = 0.023 \times 240.25 \\  = 5.52575

We have the final answer as

<h3>5.53 J</h3>

Hope this helps you

3 0
3 years ago
Consider a ball (with moment of inertia I=2/5MR^2) which bounces elastically
Oliga [24]

vn = 10nV tanθ 7 (n even), and vn = (10n−4) V tanθ 7 (n odd).

4 0
3 years ago
Read 2 more answers
A cylinder container can hold 2.45L of water. Its radius is 4.00 cm. What is the volume of it in cubic centimeters? (π=3.14)
Misha Larkins [42]

Answer:

Hey Again!

Your answer is 2450 cm3 !

Explanation:

Volume of cylinder = V=πr2h

2.45L = 2450mL

1mL = 1 cm cubed  

2450mL = 2450 cm cubed

*substitute values in*

I HOPE THIS HELPS YOU!!

7 0
3 years ago
An engineer examining the oxidation of SO 2 in the manufacture of sulfuric acid determines that Kc = 1.7 x 108 at 600 K:
kozerog [31]

Answer: p_{SO_2}=0.017atm

Explanation:

We are given:

K_c=1.7\times 10^8

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

Where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 600K

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

\Delta ng = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=1.7\times 10^8\times (0.0821\times 600)^{-1}\\\\K_p=3.4\times 10^6

The chemical reaction follows the equation:

                 2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

The expression for K_p for the given reaction follows:

K_p=\frac{(p_{SO_3})^2}{ p_{O_2}\times {(p_{SO_2})^2}}

We are given:

p_{SO_3}=300atm   p_{O_2}=100atm

Putting values in above equation, we get:

3.4\times 10^6=\frac{(300)^2}{100\times {(p_{SO_2})^2}}

p_{SO_2}=0.017atm

Hence, the partial pressure of the SO_2 at equilibrium is 0.017 atm.

3 0
3 years ago
A uniform piece of sheet steel is shaped as in the figure below. (Both axes are marked in increments of 2). Compute the x and y
Elena-2011 [213]
"increments of 8" means the major divisions are 0,8,16,24 ? 

<span>x axis, calculate the moment arms from 0 </span>
<span>3x4, 2x12, 1x20 </span>
<span>from an arbitrary C </span>
<span>3(c-4) + 2(c-12) + (c-20) = 0 </span>
<span>3c - 12 + 2c -24 + c - 20 = 0 </span>
<span>6c = 56 </span>
<span>c = 9.33 </span>

<span>y axis </span>
<span>3x3, 1x12, 2x20 </span>
<span>3(c-4) + 1(c-12) +2 (c-20) = 0 </span>
<span>3c - 12 + c - 12 + 2c - 40 = 0 </span>
<span>6c = 64 </span>
<span>c = 10.67 </span>

<span>so center is x = 9.33, y = 10.67 </span>
5 0
3 years ago
Read 2 more answers
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