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olchik [2.2K]
3 years ago
7

A weightlifter pulls on a 225 kg bar with 1600 N of force, but the bar does not move. How much work is performed?

Physics
1 answer:
KIM [24]3 years ago
6 0

Answer:

Not alot

I think its 24.5N

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As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
Oksana_A [137]

Answer:

a.Attractive

2.31531\times 10^{-16}\ N

Explanation:

When it comes to charges, the charges which are alike repel each other and the charges which are different will attract each other.

Here, there is a proton and electron which are different particles hence, they will attract each other.

q_1=q_2 = Charge of electron and proton = 1.6\times 10^{-19}\ C

r = Distance between them = 997 nm

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Force is given by

F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(997\times 10^{-9})^2}\\\Rightarrow F=2.31531\times 10^{-16}\ N

The force of attraction between the particles will be 2.31531\times 10^{-16}\ N

8 0
3 years ago
Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a
ad-work [718]

Answer:

Maximum speed of the car is 17.37 m/s.

Explanation:

Given that,

Radius of the circular track, r = 79 m

The coefficient of friction, \mu=0.39

To find,

The maximum speed of car.

Solution,

Let v is the maximum speed of the car at which it can safely travel. It can be calculated by balancing the centripetal force and the gravitational force acting on it as :

v=\sqrt{\mu rg}

v=\sqrt{0.39\times 79\times 9.8}

v = 17.37 m/s

So, the maximum speed of the car is 17.37 m/s.

6 0
3 years ago
Question for the day!
Alex17521 [72]

Answer:

1. <--> A.

2. <--> C.

3. <--> D

4. <--> B.

explanation: i know my science!

3 0
3 years ago
Read 2 more answers
100 Points!!!
Kaylis [27]

(1) The image of an object placed further from the lens than the focal point will be upside down and smaller than the object.

(2) When light rays reflect, they bounce back.

(3)  Images formed by a concave lens will look magnified.

(4) When light rays enter a different medium, they bend.

<h3>1.0 Object placed further from the lens than the focal point</h3>

The image of an object placed further from the lens than the focal point will be diminished and inverted.

Thus, the correct answer will be "upside down and smaller than the object".

<h3>2.0 What is reflection of light?</h3>

The ability of light to bounce back when it strike a hard surface is known as refection.

<h3>3.0 Image formed by concave lens</h3>

A concave lens is diverging lens is usually virtual, erect and magnified.

<h3>4.0 Refraction of light</h3>

The change in speed of light when it travels from medium to another medium is known as refraction. Refraction is also, the ability of light to bend around obstacles.

Learn more about reflection and refraction of light here: brainly.com/question/1191238

4 0
2 years ago
17 copper wires of length l and diameter d are connected in parallel to form a single composite conductor of resistance R. What
Lubov Fominskaja [6]

Answer:

\frac{D}{d} = 4.12

Explanation:

As we know that resistance of one copper wire is given as

r = \rho \frac{L}{a}

here we know that

a = \pi (\frac{d}{2})^2

now we have

r = \rho \frac{L}{\pi (\frac{d^2}{4})}

r = \rho \frac{4L}{\pi d^2}

now we know that such 17 resistors are connected in parallel so we have

R = \frac{r}{17}

R = \rho \frac{4L}{17 \pi d^2}

Now if a single copper wire has same resistance then its diameter is D and it is given as

R = \rho \frac{4L}{\pi D^2}

now from above two equations we have

\rho \frac{4L}{\pi D^2} = \rho \frac{4L}{17 \pi d^2}

D^2 = 17 d^2

now we have

\frac{D}{d} = 4.12

3 0
2 years ago
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