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Harlamova29_29 [7]
3 years ago
7

A glass of water sitting in direct sunlight evaporates over time. Explain this phase change in terms of the types of heat transf

er that occur.
Physics
2 answers:
Mila [183]3 years ago
7 0

Answer:

As material in a liquid phase increases his temperature over a given value, it starts to change is a phase, from liquid to gas phase.

Now, the water in the glass is in the liquid phase, and as the sunlight impacts, it starts to raise up the temperature of the water.

Now, this change of phase depends on the pressure of the material (less pressure needs less heat to change of phase), this means that the water that is directly in the "top" (that is only experiencing the atmospheric pressure) will start to evaporate slowly.

Then the process is the next:

Liquid water in the glass:

The sunlight transmits some heat tho the liquid water in the glass:

When the heat reaches a given point, some of the liquid water changes of phase to a more chaotic one, the gas phase (vapor of water)

dedylja [7]3 years ago
3 0
Over time the temperature of the water is going to go up. When the temperature goes up the waters molecules move a lot more than usual, which then causes the water to transform from a liquid to a gas.
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laiz [17]
The resistance R of a wire is given by:
R= \frac{\rho L}{A}
where 
\rho is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire.

For the wire in the problem, the resistivity is (copper resistivity) \rho=1.68 \cdot 10^{-8} \Omega m. The length of the wire is L=1.3 m, while the cross-sectional area is
A=\pi r^2 = \pi ( \frac{d}{2})^2 = \pi ( \frac{0.30 \cdot 10^{-3} m}{2} )^2 =7.07 \cdot 10^{-8} m^2

so the resistance of the wire is:
R= \frac{(1.68 \cdot 10^{-8} \Omega m)(1.3 m)}{7.07 \cdot 10^{-8} m^2}=0.31 \Omega
4 0
3 years ago
A father uses a rope to pull a child on a sled at a constant speed. of the ones listed which forces are present?
Amanda [17]

All the forces may be present.

The child on the sled has a weight- which is due to the force of gravity on the child and the sled.

The sled and the child exert a force on the ground equal to the combined weight of the sled and the child. The ground exerts a normal force on the sled.

The force used by the father to pull the sled is the applied force.

The sled slides on the ground and as a result, the force of friction exists between the ground and the sled, directed opposite to the direction of the motion of the sled.

The father pulls the sled using a rope. As a result, the rope is under Tension.

As the sled moves it also experiences a force of air resistance, which is dependent on the sled's speed.

However, since the father pulls the sled along with constant speed, the sum of all the forces acting on the sled is zero.

Since there is no movement in the upward or downward directions, the weight of the child and the sled is equal to the normal force acted upon the sled by the ground.

The force applied by the father on the rope is equal to the tension in the rope.

Friction and air resistance act opposite to the direction of motion of the sled. for the sled to move at constant speed, the tension in the rope must be equal to the sum of the forces due to friction and air resistance.

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3 years ago
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Its d. Meters per second
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3 years ago
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kykrilka [37]

Answer:

So, we can assemble the options based or evaluation of there properties regarding getting an equilibrium or balanced state in a given time.We have the following rankings attributed to the elements:

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Explanation:

<u>Attaining equilibrium matters:</u>

When the materials are placed inside the oven, they attain a high temperature value causing it to be non touchable but some of the items has low value to attain the equilibrium state when comes in contact with other mediums. As these materials are also arranged based on that analyses.

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