Answer:
P = -1.67 dP
Explanation:
given,
myopic lawyer has a far point of = 60.0 cm = 0.6 m
If a person is suffering from myopia then he cannot see the farthest object clearly.
Image of far object does not form on the retina so, the image appear to be blur.
using lens formula



P = -1.67 dP
Answer:
The correct question is:
"Find the energy each gains"
The energy gained by a charged particle accelerated through a potential difference is given by

where
q is the charge of the particle
is the potential difference
For a proton,

And since 
The energy gained by the proton is

For an alpha particle,

Therefore, the energy gained is

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

So the energy gained is the same as the proton:

Answer:
2.5 x 10^{5} J
Explanation:
weight = 5,000 N
coefficient of friction = 0.05
distance = 1000 m
how much work is done by the dogs pulling the sledge
work done = force x coefficient of friction x distance
work done = 5000 x 0.05 x 1000 = 2.5 x 10^{5} J
D. used by the entire scientific community
B. more accurate system of measurement