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3 years ago

A convex mirror is placed to the right of an object. The image formed by the mirror will be a

Physics

2 answers:

Harrizon [31]3 years ago

6 0

I think it’s C but I’m not too sure

Amanda [17]3 years ago

4 0

<h3><u>Answer;</u></h3>

C.) Virtual Image that appears on the right side of the mirror.

A convex mirror is placed to the right of an object. The image formed by the mirror will be a <u><em>Virtual Image that appears on the right side of the mirror. </em></u>

<h3><u> Explanation;</u></h3>

<em><u>A virtual image is an image that can not be formed on a screen. This type of an image is formed when the rays of light appear to meet at a point after reflection or refraction. Virtual images are always erect or upright.</u></em>
A real image on the other hand, is an image that can be formed on a screen. Real image is formed when the rays of light meet at some point after reflection or refraction. Real images are always inverted.

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What is the resultant displacement of the two vectors below

NeX [460]

Answer:

The resultant displacement is 5.8 cm, 31° South of the West axis ⇒ 4th

answer

Explanation:

<u><em>A resultant vector</em></u> is the combination of two or more single vectors

If the two vectors are perpendicular, then

<em><u>The magnitude</u></em> of the resultant vector = $\sqrt{x^{2}+y^{2}}$ ,where

x represents the horizontal vector and y represents the vertical vector

<em><u>The direction</u></em> of the resultant vector is $tan^{-1}\alpha$ , where α

is the angle between the horizontal vector and the resultant vector

Vector 1 is 5 cm due to West-axis

Vector 2 is 3 cm due to South-axis

We need to find the resultant displacement of them

The West and South are perpendicular

The West is the horizontal vector and South is the vertical vector

The magnitude of the resultant displacement s is:

$s=\sqrt{(5)^{2}+(3)^{2}}$

$s=\sqrt{25+9}$

$s=\sqrt{34}=5.8$

The direction of the resultant displacement s is:

$tan^{-1}\frac{3}{5}=31$ ° south of the west (between the west and

the resultant displacement)

<em>The resultant displacement is 5.8 cm, 31° South of the West axis</em>

6 0

3 years ago

The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of

Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

2, average velocity = -64.8 m/s

3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given by;

$y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}$

(1)

$y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s$

(2)

$y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s$

(3)

$y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s$

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0

3 years ago

Answer all 3 parts of this essay question: A) (5pts) If you have a Periodic Table that is NOT color coded, describe where to loo

cestrela7 [59]

Answer:

A) If you look at the vertical rows you can tell how many electrons there are on the outer shell eg. Group 7 (eg. nitrogen) has 7 electrons on its outer shell

B) They are in the same group

C) Helium,Argon and Organessom are all Nobel gasses

8 0

3 years ago

I need some serious help, i do not understand this question!!

Shkiper50 [21]

The position where the package strikes the ground is 136.3m.

<h3>Time of motion of the package</h3>

Use the following kinematic equation;

h = vt + ¹/₂gt²

179 = 47t + ¹/₂(9.8)t²

179 = 47t + 4.9t²

4.9t² + 47t - 179 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 47, c = -179

t = 2.9 seconds

<h3>Horizontal distance traveled by the package</h3>

X = vt

X = 47m/s x 2.9 s

X = 136.3 m

Thus, the position where the package strikes the ground is 136.3m.

Learn more about time of motion here: brainly.com/question/2364404

#SPJ1

4 0

2 years ago

Determine the MA based on the diagram below.

artcher [175]

There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
$MA = \frac{L_{e} }{ L_{r} }$

Where $L_{e}$ is the length of the Effort Arm(the subscript "e" stands for Effort), and $L_{r}$ stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

$L_{e}$ = 15m.
$L_{r}$ = 7m.

Therefore, $L_{e}$ / $L_{r}$ = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0

3 years ago

Read 2 more answers