<u>Solution:</u>
a) The natural frequency
b)
A part made from annealed AISI 1018 steel undergoes a 20 percent cold-work operation. Obtain the yield strength and ultimate str
1 answer:
Answer:
yield strength before cold work = 370 MPa
yield strength after cold work = 437.87 MPa
ultimate strength before cold work = 440 MPa
ultimate strength after cold work = 550 MPa
Explanation:
given data
AISI 1018 steel
cold work factor W = 20% = 0.20
to find out
yield strength and ultimate strength before and after the cold-work operation
solution
we know the properties of AISI 1018 steel is
yield strength σy = 370 MPa
ultimate tensile strength σu = 440 MPa
strength coefficient K = 600 MPa
strain hardness n = 0.21
so true strain is here ∈ = = 0.223
so
yield strength after cold is
yield strength =
yield strength =
yield strength after cold work = 437.87 MPa
and
ultimate strength after cold work is
ultimate strength =
ultimate strength =
ultimate strength after cold work = 550 MPa
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Explanation:
Points to consider:
We need to take the input from the user
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Manhattan:
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Code
#include<stdio.h>
#include<math.h>
struct Point{
int x, y;
};
int manhattan(Point A, Point B){
return abs(A.x - B.x) + abs(A.y- B.y);
}
float euclidean(Point A, Point B){
return sqrt(pow(A.x - B.x, 2) + pow(A.y - B.y, 2));
}
int main(){
struct Point A, B;
printf("Enter x and Y for first point: ");
int x, y;
scanf("%d%d", &x, &y);
A.x = x;
A.y = y;
printf("Enter x and Y for second point: ");
scanf("%d%d", &x, &y);
B.x = x;
B.y = y;
printf("Manhattan Distance: %d\n", manhattan(A, B));
printf("Euclidian Distance: %f\n", euclidean(A, B));
}
Sample output
Answer:
Explanation:
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