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muminat
3 years ago
5

Where are the ar manufacturers not fitting the engine in the high end sport cars

Engineering
1 answer:
fomenos3 years ago
8 0

Answer:

it depends on the but i would recommend check in the front next to the turbo intake.

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A composite wall is composed of 20 cm of concrete block with k = 0.5 W/m-K and 5 cm of foam insulation with k = 0.03 W/m-K. The
wariber [46]

Answer:

4.8°C

Explanation:

The rate of heat transfer through the wall is given by:

q=\frac{Ak}{L}dT

\frac{q}{A}=\frac{k}{L}dT

Assumptions:

1) the system is at equilibrium

2) the heat transfer from foam side to interface and interface to block side is equal. There is no heat retention at any point

3) the external surface of the wall (concrete block side) is large enough that all heat is dissipated and there is no increase in temperature of the air on that side

{k_{fi}= 0.03 W/m.K

{L_{fi}= 5 cm = 0.05 m

{T_{fi}= 25 \°C

{k_{cb} = 0.5 W/m.K

{L_{cb}= 20 cm = 0.20 m

{T_{cb}= 0 \°C

{T_{m}= ? \°C = temperature at the interface

Solving for {T_{m} will give the temperature at the interface:

\frac{q}{A}=\frac{k_{fi} }{L_{fi} }(T_{fi} -T_{m})=\frac{k_{cb} }{L_{cb} }(T_{m} -T_{cb})

\frac{0.03}{0.05 }(25 -T_{m})=\frac{0.5}{0.2}(T_{m} -0})

15 -0.6T_{m}=2.5T_{m}

3.1T_{m}=15

T_{m}=4.8

3 0
3 years ago
What happens to a commercial airline at cruising altitude if the pilot does not touch the throttles?
jolli1 [7]

Answer:

it slows down

Explanation:

8 0
3 years ago
A heat pump designer claims to have an air-source heat pump whose coefficient of performance is 1.8 when heating a building whos
Anit [1.1K]

Answer:

The claim is valid.

Explanation:

Let assume that heat pump is reversible. The coefficient of performance for the heat pump is:

COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}

COP_{HP} = \frac{300\,K}{300\,K-260\,K}

COP_{HP} = 7.5

The claim is valid as real heat pumps have lower coefficients of performance.

3 0
3 years ago
Traffic at a roundabout moves
sweet-ann [11.9K]

Answer:

b-counter-clockwise

Explanation:

3 0
3 years ago
Coal fire burning at 1100 k delivers heat energy to a reservoir at 500 k. Find maximum efficiency.
Marizza181 [45]

Answer:

<em>55%</em>

Explanation:

hot reservoir = 1100 K

cold reservoir = 500 K

<em>This is a Carnot system</em>

For a Carnot system, maximum efficicency of the system is given as

Eff = 1 - \frac{Tc}{Th}

where Tc = temperature of cold reservoir = 500K

Th = temperature of hot reservoir = 1100 K

Eff = 1 - \frac{500}{1100}

Eff = 1 - 0.45 = 0.55 or<em> 55%</em>

7 0
3 years ago
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