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Lady bird [3.3K]
3 years ago
5

Name the five points where product should be scanned during it's path throughout the warehouse.

Engineering
1 answer:
Oxana [17]3 years ago
7 0

Answer and Explanation:

A warehouse can be defined as a place:

is a spot or building, where the articles are kept, put away or in some cases prepared.  

Depending on the sort of use, the checkpoints may fluctuate.  

There can be numerous sorts, for example, pressing, railroad wagon, cool stockpiling, and so on.  

Suppositions are caused in regards to each shape and a few checkpoints for an item to can be summed up.  

  • The point of entry, where it ought to be through into the product house.  
  • Security checkpoint, where the item belonging is to be protected.  
  • Palletized segment, where the item is to be put in a spot and it determines the location of that item in the house.  
  • Quality or bundling segment, where the item must be tried and improved.  
  • Leave segment, through which it must be taken out for further procedures.  

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Crazy boy [7]

The answer is choice C

Explanation:

As during construction ,the site is cleared for all debris before laying out the foundation. Even the sewer lines are dug out .

So it will be useful for the construction crews to  connect the pipes to the sewer lines before the foundation is poured.

But usually the steps take in construction activity is:- first the site is cleared for the foundation to be poured  and once the foundation wall is set , then all utilities , including plumbing and electrical activities are done.,

After this process is over, the city inspector comes to check whether the foundation has been laid down as per the code of construction.

Only after that the rest of the construction activity follows through.

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3 years ago
Rubber bushings are used on suspensions to
Harlamova29_29 [7]
D. All of the above
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3 years ago
A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28
Delicious77 [7]

Answer:

5984.67N

Explanation:

A 14 inch diameter pipe is decreased in diameter by 2 inches through a contraction. The pressure entering the contraction is 28 psi and a pressure drop of 2 psi occurs through the contraction if the upstream velocity is 4.0 ft/sec. What is the magnitude of the resultant force (lbs) needed to hold the pipe in place?

from continuity equation

v1A1=v2A2

equation of continuity

v1=4ft /s=1.21m/s

d1=14 inch=.35m

d2=14-2=0.304m

A1=pi*d^2/4

0.096m^2

a2=0.0706m^2

from continuity once again

1.21*0.096=v2(0.07)

v2=1.65

force on the pipe

(p1A1- p2A2) + m(v2 – v1)

from bernoulli

p1 + ρv1^2/2 = p2 + ρv2^2/2

difference in pressure or pressure drop

p1-p2=2psi

13.789N/m^2=rho(1.65^2-1.21^2)/2

rho=21.91kg/m^3

since the pipe is cylindrical

pressure is egh

13.789=21.91*9.81*h

length of the pipe is

0.064m

AH=volume of the pipe(area *h)

the mass =rho*A*H

0.064*0.07*21.91

m=0.098kg

(193053*0.096- 179263.6* 0.07) + 0.098(1.65 – 1.21)

force =5984.67N

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3 years ago
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Answer:

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Explanation:

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