All categories

3 years ago

Name the five points where product should be scanned during it's path throughout the warehouse.

Engineering

1 answer:

Oxana [17]3 years ago

7 0

Answer and Explanation:

A warehouse can be defined as a place:

is a spot or building, where the articles are kept, put away or in some cases prepared.

Depending on the sort of use, the checkpoints may fluctuate.

There can be numerous sorts, for example, pressing, railroad wagon, cool stockpiling, and so on.

Suppositions are caused in regards to each shape and a few checkpoints for an item to can be summed up.

The point of entry, where it ought to be through into the product house.

Security checkpoint, where the item belonging is to be protected.

Palletized segment, where the item is to be put in a spot and it determines the location of that item in the house.

Quality or bundling segment, where the item must be tried and improved.

Leave segment, through which it must be taken out for further procedures.

You might be interested in

How does Hydro Technology and Hydro Energy Help with Global Water Issues?

GrogVix [38]

It would have environmental and societal impacts

5 0

2 years ago

Sawing stock to reduce its thickness is known as __________ .

rjkz [21]

Answer:

resawing

Explanation:

8 0

3 years ago

An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and

k0ka [10]

Answer:

A.) 0.3088

B.) 0.0017

C.) part A

Explanation:

A.)

$z1=$ $\frac{\left(150-137\right)}{27.7}$ $=0.4693$

$z2=\frac{\left(201-137\right)}{27.7}=2.3105$

$P(0.4693$

B.)

$z1=\frac{150-137}{27.7/ \sqrt{39}} =2.9309\\z2=\frac{201-137}{27.7/ \sqrt{39}}=14.4289$

$\\P(2.9309$

C.) Since the seat performance for an individual pilot is more important than 39 different pilots.

3 0

3 years ago

Read 2 more answers

Assume the work done compressing the He gas is -63 kJ and the internal energy change of the gas is 79 kJ. What is the heat loss

klemol [59]

Answer:

Heat gain of 142 kJ

Explanation:

We can see that job done by compressing the He gas is negative, it means that the sign convention we are going to use is negative for all the work done by the gas and positive for all the job done to the gas. With that being said, the first law of thermodynamics equation will help us to solve this problem.

Δ $U = Q + W$ ⇒ $Q =$ Δ $U -W$

$Q = 79 - (-63) = 142 kJ$

Therefore, the gas gained heat by an amount of 142 kJ.

3 0

3 years ago

What is the De Broglie wavelength of an electron under 150 V acceleration?

yanalaym [24]

Answer:

0.1 nm

Explanation

Potential deference of the electron is given as V =150 V

Mass of electron $m=9.1\times 10^{-31}$

Let the velocity of electron = v

Charge on the electron $=1.6\times 10^{-19}C$

plank's constant h = $6.67\times 10^{-34}$

According to energy conservation $eV =\frac{1}{2}mv^2$

$v=\sqrt{\frac{2eV}{M}}=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{-6}m/sec$

Now we know that De Broglie wavelength $\lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times10^6 }=0.100\times 10^{-9}m=0.1nm$

4 0

3 years ago

Read 2 more answers