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Lady bird [3.3K]

3 years ago

5

Name the five points where product should be scanned during it's path throughout the warehouse.

1 answer:

Oxana [17]3 years ago

7 0

Answer and Explanation:

A warehouse can be defined as a place:

is a spot or building, where the articles are kept, put away or in some cases prepared.

Depending on the sort of use, the checkpoints may fluctuate.

There can be numerous sorts, for example, pressing, railroad wagon, cool stockpiling, and so on.

Suppositions are caused in regards to each shape and a few checkpoints for an item to can be summed up.

The point of entry, where it ought to be through into the product house.

Security checkpoint, where the item belonging is to be protected.

Palletized segment, where the item is to be put in a spot and it determines the location of that item in the house.

Quality or bundling segment, where the item must be tried and improved.

Leave segment, through which it must be taken out for further procedures.

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The answer is given in the explanation.

Explanation:

The circuit is as indicated in the attached figure.

From the analytical description the zener voltage is given as

$V_z=V_z_o+I_zr_z$

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The equivalent model is shown in the attached figure.

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rz is given as 30 Ω

Thus the Vzo is given as

$V_z_o=V_z-I_zr_z\\V_z_o=7.4-30*10*10^{-3}\\V_z_o=7.5-0.3\\V_z_o=7.2 V$

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$I=I_z+I_L\\I=10mA+5mA\\I=15 mA$

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$R=\dfrac{V-Vo}{I}\\186.66=\dfrac{11-V_o}{15*10^{-3}}\\V_o=8.2 V$

Considering the supply voltage is decreased by 10%

V is 10-10%*10=10-1=9 so the

$R=\dfrac{V-Vo}{I}\\186.66=\dfrac{9-V_o}{15*10^{-3}}\\V_o=6.2 V$

Now if the supply voltage is 10% high and the value of Load is removed i.e I=Iz only which is 10mA

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$R=\dfrac{V-Vo}{I'}\\186.66=\dfrac{11-V_o}{10*10^{-3}}\\V_o=9.13 V$

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