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3 years ago

Supercharged engine what it does to the car

Engineering

2 answers:

Makovka662 [10]3 years ago

8 0

They are correct because it the fuel part^

geniusboy [140]3 years ago

3 0

Answer:

A supercharger is an air compressor that increases the pressure or density of air supplied to an internal combustion engine. This gives each intake cycle of the engine more oxygen, letting it burn more fuel and do more work, thus increasing power.

Explanation:

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The following statements are about the laminar boundary layer over a flat plate. For each statement, answer whether the statemen

Nikolay [14]

Answer:

1. B. False

2. B. False

3. A. True

4. B. False

5. A. True

6. A. True

7. A. True

Explanation:

1. B. False

The relation of Reynolds' number, Reₓ to boundary layer thickness δ at a point x is given by the relation

$\delta = \dfrac{x \times C}{\sqrt{Re_x} }$

That is the boundary layer thickness is inversely proportional to the square root of the Reynolds' number so that if the Reynolds' number were to increase, the boundary layer thickness would decrease

Therefore, the correct option is B. False

2. B. False

From the relation

$Re_x = \dfrac{U_o \times x}{v}$

As the outer flow velocity increases, the boundary layer thickness diminishes

3. A. True

As the viscous force is increased the boundary layer thickness increases

4. B. False

Boundary layer thickness is inversely proportional to velocity

5. A. True

The boundary layer model developed by Ludwig Prandtl is a special case of the Navier-Stokes equation

6. A. True

Given a definite boundary layer thickness, the curve representing the boundary layer thickness is a streamline

7. A. True

The boundary layer approximation by Prandtl Euler bridges the gap between the Euler (slip boundary conditions) and Navier-Stokes (no slip boundary conditions) equations.

6 0

3 years ago

The assembly consists of two 10 mm diameter red brass C83400 coper rods AB and CD, a 15 mm diameter 304 stainless steel of EF an

My name is Ann [436]

Answer:

Therefore, the horizontal displacement of end F of rod EF is 0.4797 mm

Explanation:

solution is mentioned in steps.

6 0

3 years ago

Air enters a turbine operating at steady state at 440 K, 20 bar, with a mass flow rate of 6 kg/s, and exits at 290 K, 5 bar. The

marysya [2.9K]

Answer:

The rate of heat transfer is - 935.392 kW

Explanation:

Given;

inlet pressure, P₁ = 20 bar

inlet temperature, T₁ = 440 k

outlet pressure, P₂ = 5 bar

outlet temperature, T₂ = 290 k

inlet velocity, v₁ = 18 m/s

outlet velocity, v₂ = 30 m/s

mass flow rate, Q = 6kg/s

developed power, W = 815 kW

From steam table;

at P₁ and T₁, interpolating between T = 400 and T = 450, h₁ = 3335.52 kJ/kg

at P₂ and T₂, interpolating between T= 250 and T= 300, h₂ = 3043.5 kJ/kg

Applying steady state energy balance equation;

$\frac{Q}{m} -\frac{W}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2})\\\\\frac{Q}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2}) +\frac{W}{m}$

substitute values above into this equation and evaluate the rate of heat transfer

$\frac{Q}{m} = h_2-h_1 +\frac{1}{2} (v_2{^2} -v_1{^2}) +\frac{W}{m}\\\\\frac{Q}{m} = 3043.5 - 3335.52 +\frac{1}{2000} (30{^2} -18{^2}) + \frac{815}{m} \\\\\frac{Q}{m} = -291.732 + \frac{815}{m}\\\\\frac{Q}{m} = \frac{815}{m} -291.732\\\\Q = 815 - m(291.732)\\Q = 815 - 6*291.732\\\\Q = 815-1750.392 = -935.392 \ kW$

Therefore, the rate of heat transfer, in kW, for a control volume enclosing the turbine is - 935.392 kW

4 0

3 years ago

A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture tough

sp2606 [1]

Answer:

Not subject to detection

Explanation:

Assuming the value of strain fracture toughness is 77 Mpa $\sqrt m$

The design stress is half hence $\sigma=0.5\times 1400=700 Mpa$

Critical flaw size, $a_c=\frac {1}{\pi}(\frac {K_{1c}}{Y/sigma})^{2}$

Where Y is dimensionless parameter, $\sigma$ is applied stress, $K_{1c}$ is plane strain fracture toughness, $a_c$ is critical length of surface crack

$a_c=\frac {1}{\pi}(\frac {77}{1*700})^{2}= 0.0038515496\approx 0.00385m$

The critical length of surface crack is therefore 3.85 mm, which is less than detection apparatus size given as 4 mm

Since the critical flaw size is less than the resolution limit of flaw detection apparatus, the critical flaw for this plate is not subjected to detection.

5 0

3 years ago

If the symbol is on the top and bottom of the reference line, we call this __________ sides.

sattari [20]

I think the correct answer is B

6 0

3 years ago