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algol13
3 years ago
7

The acceleration of The Munster’s car is 9.71 m/s2 when he applies 5050 N of net force (by way of the engine). What is the mass

of his car in kilograms?
520 kg


49,000 kg


0.0019 kg


none of the above
Physics
1 answer:
Crazy boy [7]3 years ago
8 0

Force is defined as the product of mass of the body and its acceleration.

In the question we are given,

Force (F) = 5050 N

Acceleration (a) = 9.71 m/s^{2}

Now, According to Newton's second law of motion ,

            F= m*a

Dividing both sides by a, we get

            \frac{F}{a}=m

or,

            m=\frac{F}{a}

Putting the values of F and a we get,

           m= \frac{5050}{9.71}

           m=520.08 kg

Hence, the mass of Munster's Car ≈ 520 kg.

<h3>Answer: 520 kg</h3>
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Physics Homework MathPhys homie if you see this pls help
cluponka [151]

Answer:

1. -8.20 m/s²

2. 73.4 m

3. 19.4 m

Explanation:

1. Apply Newton's second law to the car in the y direction.

∑F = ma

N − mg = 0

N = mg

Apply Newton's second law to the car in the x direction.

∑F = ma

-F = ma

-Nμ = ma

-mgμ = ma

a = -gμ

Given μ = 0.837:

a = -(9.8 m/s²) (0.837)

a = -8.20 m/s²

2. Given:

v₀ = 34.7 m/s

v = 0 m/s

a = -8.20 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (34.7 m/s)² + 2 (-8.20 m/s²) Δx

Δx = 73.4 m

3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.

d = v₀t

d = (34.7 m/s) (0.56 s)

d = 19.4 m

6 0
3 years ago
What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 29.0 km/h and the co
bazaltina [42]

Answer:

Explanation:

Let the radius of track required be r.

Centripetal force will be provided by frictional force which will be equal to

m v²/ r

Frictional force = mg x μ

So

m v² /r = mg μ

r = v² / μ g =

  v = 29 km /h = 8.05 m /s

r =( 8.05 x 8.05 ) /( .32 x 9.8 ) = 20.66 m

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alisha [4.7K]

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7 0
3 years ago
A 2500 N force accelerates a car at a rate of 3.0 m/s^2. What is the car’s mass? 250 kg
Ronch [10]

Apply Newton's second law to the car's motion:

F = ma

F = net force, m = mass, a = acceleration

Given values:

F = 2500N, a = 3.0m/s²

Plug in and solve for m:

2500 = m(3.0)

m = 830kg

5 0
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