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Advocard [28]
3 years ago
14

you go out to dinner and the bill comes to $35.51. how much should you tip if you want the tip to be 20% of the bill.​

Chemistry
2 answers:
agasfer [191]3 years ago
8 0
35.51 times 0.2 is 7.102
So you should tip $7.102
Katarina [22]3 years ago
4 0
£42.6 is the answer. (36.51 * 120)/100
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How many moles of CH3 are in 60 grams of CH3 ?
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Answer: There are 3.99 .

Explanation:

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Which action do researchers take to make advances in science?
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A solution has a [H3O+] of 1x 10-5 M. What is the [OH-] of the solution? (5 points)
White raven [17]

Answer:

1x10^–9 M

Explanation:

From the question given,

Concentration of hydronium ion, [H3O+] = 1x10^-5 M.

Concentration of Hydroxide ion, [OH-] =..?

The concentration of the hydroxide ion, [OH-] can be obtained as follow:

[H3O+] x [OH-] = 1x10^–14

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8 0
3 years ago
One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su
Tpy6a [65]

Answer : The percent purity of Fe_2O_3 in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

Fe_2O3+3CO\rightarrow 2Fe+3CO_2

First we have to calculate the mass of Fe.

\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}

Molar mass of Fe = 55.8 g/mole

\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole

Now we have to calculate the moles of Fe_2O_3

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of Fe_2O_3

So, 3.15\times 10^4mole of Fe produced from \frac{3.15\times 10^4}{2}=15750 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3

Molar mass of Fe_2O_3 = 159.69 g/mole

\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg

Now we have to calculate the percent purity of Fe_2O_3 in the original sample.

Mass of original sample = 2.86\times 10^3kg

\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100

\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%

Therefore, the percent purity of Fe_2O_3 in the original sample is 87.94 %

3 0
3 years ago
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otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

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Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

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From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

And we have the value of half life, so, replacing we have:

λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
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