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2 years ago

How do the circulatory system and respiratory system interact and work together?

2 answers:

8 0

I would say because the respiratory system brings in the oxygen for the body and the circulatory system moves it throughout the body with the blood

zheka24 [161]2 years ago

5 0

Answer:

The respiratory system helps you breath meanwhile your circulatory system helps the oxygen circulate in your blood throughout your body.

Explanation:

It helps you do many tasks like running, sprinting, etc.

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If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity

olga nikolaevna [1]

<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

Number of moles = Mass /molar mass

= (10.7g NH4Cl)/(53.5g/mol NH4Cl)

= 0.200 moles NH4Cl

Then we convert to liters:

= (800mL)*(1L/1000mL) = 0.800L

Therefore; molarity = 0.2moles/0.8L

= 0.25M

6 0

2 years ago

What do all group 2 elements have in common? (2 points) they all gain two electrons to form a stable outer energy level. They fo

NemiM [27]

The correct answer would be the last option. The property that is common to all group 2 elements is that they tend to form ionic bonds by losing electrons making these atoms positive charge. They are called cations. These elements are beryllium, magnesium, calcium, strontium, and radium.

3 0

3 years ago

Read 2 more answers

Red blood cells contain an enzyme called carbonic anhydrase, which catalyzes the reversible reaction whereby carbon dioxide and

Dvinal [7]

Carbon o2 to bed the oxygen of the

3 0

2 years ago

What is the percent composition of aluminum in the ore bauxite (AI2O3)?

Schach [20]

Answer:

Molar mass of Al2O3 = 101.961276 g/mol

This compound is also known as Aluminium Oxide.

Convert grams Al2O3 to moles or moles Al2O3 to grams

Molecular weight calculation:

26.981538*2 + 15.9994*3

Percent composition by element

Element Symbol Atomic Mass # of Atoms Mass Percent

Aluminium Al 26.981538 2 52.925%

Oxygen O 15.9994 3 47.075%

Explanation:

Percent composition by element

Element Symbol Mass Percent

Aluminium Al 52.925%

Oxygen O 47.075%

6 0

2 years ago

S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?

Brilliant_brown [7]

Answer: There are 6.9 mol of $F_{2}$ are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

$S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)$

Here, 1 mole of S is reaction with 3 moles of $F_{2}$ which means 1 mole of S requires 3 moles of $F_{2}$ .

Therefore, moles of $F_{2}$ required to react completely with 2.30 moles S are calculated as follows.

$1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}$

Thus, we can conclude that there are 6.9 mol of $F_{2}$ are required to react completely with 2.30 mol of S.

3 0

3 years ago