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telo118 [61]
3 years ago
8

Animals return water to the air through:

Chemistry
2 answers:
KengaRu [80]3 years ago
6 0
Animals return gained water to the atmosphere through <span>Perspiration which is a method of sweating</span>
andrew-mc [135]3 years ago
4 0
That would be perspiration.
Hope it helps!
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OK OK ONE MORE TRY
babunello [35]
Your question can be found online! Just draw one of these diagrams

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3 years ago
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Una pieza de silicio tiene un volumen de 8 cm3. ¿Cuál es su masa? *
Maurinko [17]

Answer:

el volumen es igual a masa decidida por densidad

8 0
2 years ago
Argon gas has a boiling point of -197 °C. Which of the following diagrams best represents the
Paha777 [63]

Answer:

(a)

Explanation:

Hello,

In this case, the temperature required to boil argon, it means, transform it from liquid to gas is -197 °C. In such a way, since the temperature inside the steel sphere is -190 °C, which is greater than the boiling point, we realize argon is gaseous, therefore, the molecules will be spread inside the sphere as they will be moving based on the kinetic theory of gases.

For that reason, answer is scheme (a).

Best regards.

6 0
3 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
Which of the following ways can the volume of a gas be changed, without changing its mass? Select all that apply.
pochemuha

Answer:

It can be spread into a smaller container

It can ve spread out into a larger container

It can be dissolved into a liquid

8 0
2 years ago
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