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2 years ago

What is 1/5 of 11? This is so annoying!

1 answer:

Nutka1998 [239]2 years ago

6 0

$\dfrac{1}{5}\ of\ 11:\\\\\dfrac{1}{5}\cdot11=\dfrac{11}{5}=\dfrac{10+1}{5}=\dfrac{10}{5}+\dfrac{1}{5}=\boxed{2\dfrac{1}{5}}$

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Mrs. treble charges her music students $25 per lesson plus a recital fee of $50. How many lessons can a student take if he/she d

Brilliant_brown [7]

Answer:

2 lessons

Step-by-step explanation:

$25+$50=$75

$75+$75=$150

$150 for 2 lessons not passing the budget of $175

7 0

3 years ago

Please help!!!! largest, and smallest 6 digit number divisible by 2,3,4,5,6,8,9,10

Vadim26 [7]

Answer:

Basically it has to be divisible by 8, 9, and 10 because any number that is divisible by 2, 3, 4, 5, 6 must also be divisible by 8, 9 and 10. We know that the number has to end in 0, the sum of its digits must be divisible by 9 and the last three digits must be divisible by 8. Therefore, the smallest number is 10080 and the largest is 999360.

3 0

3 years ago

The sum of 39 and a number

harkovskaia [24]

Answer: 39 + n

Explanation:

Sum —> addition
A number —> the unknown value, variable

6 0

3 years ago

Solve x2+4x+6=0 by graphing

klemol [59]

Answer: x = -2±√2 i or no real roots. See the explanation below.

Step-by-step explanation:

If you draw the graph, you will notice that there are no common points or you can say that there are no x-intercepts.

This means that the equation doesn't have any real roots.

If there are 2 common points (2 x-intercepts) then there are 2 real roots (answers.)

If there is only one common point (vertex is on x-axis) then there is only 1 real root.

If there aren't any common points (no x-intercepts) then there are no real roots.

So first, I'm gonna convert the equation into function and convert the standard form to vertex form.

$x^2+4x+6=0\\y=x^2+4x+6\\y=(x^2+4x+4)-4+6\\y=(x+2)^2+2$

We notice that the vertex is at (-2,2), the graph doesn't have x-intercepts (Graph below)

So the answer is clearly complex.

If you solve this by solving the equation then it'll be.

$x^2+4x+6=0\\x= \frac{-b+-\sqrt{b^2-4ac}}{2a} \\x=\frac{-4+-\sqrt{16-24} }{2}\\x=\frac{-4+-\sqrt{-8} }{2}\\\\x=\frac{-4+-2\sqrt{2}i }{2}\\\\x={-2+-1\sqrt{2}i }\\\\$

The answer is complex.

However, you can find the value of x easily by graphing. For example.

$x^2+6x+5=0$

Factor then you get

$(x+5)(x+1)=0\\x=-5,-1$

Or you can convert it to vertex form then graph.

$y=x^2+6x+5$

$y=(x^2+6x+9)-9+5\\y=(x+3)^2-4$

The vertex is at (-3,-4) then graph parabola (x-intercepts determine the roots of quadratic equation. For the graph, parabola intercepts x at (-5,0) and (-1,0) that means both -5 and -1 both are the value of x.

Note:

From the standard form, $y=ax^2+bx+c$ The graph is called Parabola, and it's Quadratic Function.

a is how the graph is, for example. If a>0, the graph is supine parabola and if a<0 then the graph is inverted parabola.

|a| is determined if the graph is wide or narrow, the more the value of a is, the more narrow it will be. The less the value of a is, the more wide it will be.

b is what determined the change of graph (likely vertex). Without b, then it'd be $ax^2+k$ which only move y-axis and not x-axis.

c is what determined the y-intercept and y-axis. If there is no b or the value of b is 0 then the vertex is at (0,c). If there is the value of b then c is only determined the y-intercept.

4 0

3 years ago

⚠️ANSWER NEEDED QUICK, SHOW WORK TOO⚠️

KATRIN_1 [288]

Answer:

28+28=56 so 28 and 28 and the bottom will be 56

6 0

2 years ago