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hammer [34]
3 years ago
15

If m ∥ k and m ∥ ℓ, then _____

Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

\large\huge\boxed{\text{If}\ m\ ||\ k\ \text{and}\ m\ ||\ l,\ \text{then}\ k\ ||\ l}

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(URGENT) need this for today!​
Zigmanuir [339]

Answer:

right triangel

Step-by-step explanation:

the sides just add up to that i thinl

6 0
3 years ago
Use the zero product property to find the solutions to the equation (x + 2) (x + 3) = 12
Inessa05 [86]

Answer:

The solution of the equations are -6 and 1

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- We want to find the solution of the equation (x + 2) (x + 3) = 12

- <em>At first lets use the Foil method to multiply the two brackets</em>

 (x + 2) (x + 3) = (x)(x) + (x)(3) + (2)(x) + (2)(3)

 (x + 2) (x + 3) = x² + 3x + 2x + 6 ⇒ add the like term

 (x + 2) (x + 3) = x² + 5x + 6

∵ (x + 2) (x + 3) = 12

∴ x² + 5x + 6 = 12

- Subtract 12 from both sides

∴ x² + 5x - 6 = 0

- <em>Factorize the left hand side</em>

∵ x² = (x)(x)

∵ -6 = 6 × -1

∵ 6x + -1x = 5x

∴ (x + 6)(x - 1) = 0

- <em>Lets use the zero product property </em>

∵ (x + 6)(x - 1) = 0

∴ x + 6 = 0 ⇒ <em>OR</em> ⇒ x - 1 = 0

∵ x + 6 = 0

- Subtract 6 from both sides

∴ x = -6

∵ x - 1 = 0

- Add 1 to both sides

∴ x = 1

∴ The solution of the equations are -6 and 1

6 0
3 years ago
Read 2 more answers
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
A baker’s dozen (13) of cookies is on sale for $2.08.
poizon [28]
So taking this as if there are 13 dozens of cookies. First we do 13 times 12 which would be 156 cookies in total. Then 156 cookies times 2.08 is 324.48
4 0
3 years ago
Read 2 more answers
A string is 500 inches long.
SIZIF [17.4K]
Nicole 283 inches of sting left
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3 years ago
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