Question

What is the net ionic equation for the precipitation reaction between bacl2 and na2so4? a bacl2(aq + na2so4(aq ? baso4(s + 2nacl(aq b ba2+(aq + so42-(aq ? baso4(s c na+(aq + cl-(aq ? nacl(s d ba2+(aq + 2cl-(aq + 2 na+(aq + so42-(aq ? baso4(s + 2cl-(aq + 2na+(aq?

Answer 1

BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) = BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)

Ba²⁺(aq) + SO₄²⁻(aq)= BaSO₄(s)

Answer 2

Answer:

B) Ba²⁺(aq) + SO₄²⁻(aq) => BaSO₄(s)

Explanation:

To prepare the net ionic equation it is important to have the balanced precipitation reaction between BaCl₂(aq) and Na₂SO₄(aq). This is given below;

BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)

Similar to a molecular equation, which expresses compounds as molecules, an ionic equation is a chemical equation where the electrolytes in aqueous solution are expressed as dissociated ions.

However, we have both complete and net ionic equations.

The two most common forms of ionic equations are complete ionic equations and net ionic equations. The complete ionic equation indicates all of the dissociated ions in a chemical reaction. The net ionic equation cancels out ions that appear on both sides of the reaction arrow because they essentially don't participate in the reaction of interest. The ions that are canceled out are called spectator ions.

The complete ionic equation in this case is given as;

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) => BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)

We obtain the net ionic equation by cancelling out ions that appear on both sides of the reaction arrow. These ions are Na⁺ and Cl⁻. Upon cancellation, we are left with;

Ba²⁺(aq) + SO₄²⁻(aq) => BaSO₄(s)