All categories

3 years ago

. Deltas form mainly due to

Chemistry

2 answers:

Mumz [18]3 years ago

8 0

Answer:

A river delta is a landform created by deposition of sediment that is carried by a river as the flow leaves its mouth and enters slower-moving or stagnant water. This occurs where a river enters an ocean, sea, estuary, lake, reservoir, or (more rarely) another river that cannot carry away the supplied sediment.

Explanation:

have a good day /night

may i please have a branlliest

statuscvo [17]3 years ago

6 0

Answer:

Deltas form where rivers meet the ocean, and are naturally shaped by river, wave and tidal processes. Deltas are preferred locales of human habitat ion due to their high productivity, rich biodiversity, and easy transport along abundant waterways.

Explanation:

please mark brainlest

You might be interested in

Which of the following best helps to why the value of Delta H degree for the CaF_2 in water in positive? A. CaF_2(s) is insolubl

FromTheMoon [43]

Answer: Option (C) is the correct answer.

Explanation:

A positive value of enthalpy or $\Delta H$ means that energy is being absorbed from the surrounding. As $CaF_{2}$ has strong ionic bonding between both calcium and fluorine atoms. So, to break their bond we need to provide energy to it.

So, when $CaF_{2}$ is dissolved in warm water then warm water molecules will bombard with the stable bond of $CaF_{2}$ . As a result, the energy will transfer from water to the bond in order to break it. And, due to loss in internal energy then there will be consequent lowering of temperature.

When this bond is broken down then the atoms will separates into gaseous ions and these ions will be then surrounded by the water molecules. As ithe bond between $CaF_{2}$ is very strong hence, its lattice energy will be very high.

Thus, we can conclude that the statement $Ca^{2+}$ ions have very strong interactions with $F^{-}$ ions in the crystal lattice, best helps to why the value of $\Delta H$ degree for the $CaF_{2}$ in water in positive.

7 0

3 years ago

What are body tissues? (A)cells that perform different tasks(B)the main organ in the body.(C)organs in the body(D)similar cells

Lorico [155]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

How much of a sample remains after five half-lives have occurred?

timama [110]

Answer:

1/32 of the original sample

Explanation:

We have to use the formula

N/No = (1/2)^t/t1/2

N= amount of radioactive sample left after n number of half lives

No= original amount of radioactive sample present

t= time taken for the amount of radioactive samples to reduce to N

t1/2= half-life of the radioactive sample

We have been told that t= five half lives. This implies that t= 5(t1/2)

N/No = (1/2)^5(t1/2)/t1/2

Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

N/No= (1/2)^5

N/No = 1/32

Hence the fraction left is 1/32 of the original sample.

3 0

3 years ago

A fixed number of moles of an ideal gas are kept in a container of volume V and an absolute temperature T. If T and V are both d

liubo4ka [24]

Answer:

If the temperature and volume ot a gas increases, the r.m.s. velocity of the molecules in the gas will be 2 times the original r.m.s. molecular velocity.

If T doubles while V is held constant, the new net internal energy of the gas will be 2 times the original internal energy of the gas.

Explanation:

Temperature and root mean square velocity are directly proportional to one anoth. If the temperature increases, root mean square velocity also increases and vice versa, while temperature is also directly proportional to the internal energy of the gas molecules, higher the temperature, higher will be the internal energy and lower the temperature so internal energy will be decreased.

8 0

3 years ago

A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific

worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
Thermodynamics

Specific Heat Formula: $\displaystyle q = mc \triangle T$

m is mass (g)
c is specific heat capacity (J/g °C)
ΔT is the change in temperature

Explanation:

Step 1: Define

Identify variables.

m = 112 g

ΔT = 20.0 °C

q = 1004 J

Step 2: Solve for c

Substitute in variables [Specific Heat Formula]: $\displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})$
Simplify: $\displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c$
Isolate c: $\displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}$
Round [Sig Figs]: $\displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}$

∴ specific heat capacity c is equal to around 0.45 J/g °C.

---

Topic: AP Chemistry

Unit: Thermodynamics

5 0

3 years ago