the mass of potassium iodide is 0.360 g
calculation
step 1: write the balanced molecular equation
Pb(NO3)2 (aq) + 2 Ki (s)→ Pbi2(s) + 2KNO3
step 2 ; calculate the moles of Pbi2
moles = mass /molar mass
= 0.500 g / 461 .0 g/mol =0.0011 moles
step 3: use the mole ratio to calculate the moles of Ki
Ki: Pbi2 is 2:1 therefore the moles of ki = 0.0011 x 2/1 = 0.0022 moles
step 4 : find the mass of Ki
mass= moles x molar mass
=0.0022 moles x 166g/mol =0.365 g which is approximate 0.360 g
Answer:
Option 5 → 7.01 g
Explanation:
Molarity . volume (L) = Moles
This can help us to determine the moles of KOH that are in the solution.
We convert the volume from mL to L → 250 mL . 1L / 1000mL = 0.250 L
0.5 mol /L . 0.250L = 0.125 moles of KOH
Now, we only have to convert the moles to mass, by the molar mass:
Moles . molar mass = mass → 0.125 mol . 56.1 g/mol = 7.01 g
Answer:
The motion of the gas particles is random and in a straight-line. A sample of gas is contained in a closed rigid cylinder.
I hope this helps you if not soo advance sorry :)
No :) They see different parts but I am a little confuse when you say the same part ;P