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dexar [7]
3 years ago
10

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl

ock is pulled with a force of 100 N. What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?
Physics
1 answer:
o-na [289]3 years ago
8 0

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

F=ma

100=100m\times a

ma=1\ N

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

F_{100-99}=ma

F_{100-99}=1

We need to calculate the total number of masses attached to the string

Using formula for mass

m'=(100-50)m

m'=50m

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

F_{50}=m'a

Put the value into the formula

F_{50}=50m\times a

F_{50}=50\times1

F_{50}=50\ N

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

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Answer:

  q = - ( 2*sqrt(2) + 1 )*Q / 4

Explanation:

Given:

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Solution:

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                          F_c = k*Q^2 / (a*sqrt(2))^2 = k*Q^2 / 2*a^2

                          F = k*Q*q / (a / 2sqrt(2))^2 = 2*k*Q^2 / a^2

- Use Electrostatic Equilibrium conditions:

                          F_b + F_c*cos(45) = F*cos(45)

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                          { (Q/a)^2 + (Q^2 / 2*a^2*sqrt(2)) = sqrt(2)*Q*q / a^2

- Canceling all k's and a^2:

                          Q * ( 1 + (1 /2*sqrt(2)) ) =  sqrt(2)*q

                          q = - ( 2*sqrt(2) + 1 )*Q / 4

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resolution=voltage range / digital range
The voltage range in our case is from -500mV to 500mV, which gives 1000mV.
The digital range on the other hand is 2^(number of bits).
It depends on what type of bit board we are using. If the ADC we are using is a 16 bit board, then 2^16=<span>65536.
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3 years ago
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v(t) = 27 units

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The function s(t) represents the position of an object at time t moving along a line such that,

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