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zmey [24]
3 years ago
13

A parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates. A 1.0 g plastic bead, with a charg

e of -6.0 nC, is suspended between the two plates by the force of the electric field between them.
Which plate, the upper or the lower, is positively charged?
Physics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

The upper plate is positive charged.

Explanation:

From the information we have, we know that the plastic bead, carrying a negative charge of  -6 nC, is suspended between the two plates by the force of the electric field between them.

If it is suspended, this means that it is at rest. As we have two forces acting on the bead (gravity and electrostatic force), and gravity is always downward, this means that the electrostatic force must be upwards.

If this force is due to the field, as the force on a negative charge is opposite to the direction of the field, this means that the electric field created by the charge on the plates must be pointed downward.

If it points downward, as the electric field has the same direction that it would have a positive test charge, this means that the charge would go down also, away from the positive charged plate, which must be the upper one.

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dolphi86 [110]
I believe it's B. the transmission of heat across matter
6 0
3 years ago
Read 2 more answers
what kinds of investigations might have led to our current understanding of matter and energy? why is it important for scientist
lana66690 [7]

The kind of investigations might have led to our current understanding of matter and energy is research and measurement.

It is important for scientists to use the same scientific method and consistent measurement units in order to get the correct value while analayzing.

<h3>What is matter?</h3>

The matter has volume and space occupied.

When conceivable the researcher endeavors to test his speculations via painstakingly planned and controlled tests that will yield quantitative instead of subjective outcomes.

Thus, the kind of investigations might have led to our current understanding of matter and energy is research and measurement.

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6 0
2 years ago
A typical tire for a compact car is 22 inches in diameter. If the car is traveling at a speed of 60 mi/hr, find the number of re
Softa [21]

Answer:

rpm= 916.7436 rev/min

Explanation:

First determine the perimeter of the wheel, to know the horizontal distance it travels in a revolution:

perimeter= π×diameter= π × 22 inches × 0.0254(m/inche)= 1.7555m

Time we divide the speed of the car, which is the distance traveled horizontally over time unit, by the perimeter of the wheel that is the horizontal distance traveled in a revolution, this dates us the revolutions over the time unit:

revolutions per time= velocity/perimeter

velocity= (60 mi/hr) × (1609.34m/mi) = 96560m/h

revolutions per time= (96560.6m/h) / (1.7555m)= 55004.614 rev/hr

rpm= (55004.614 rev/hr) × (hr/60min)= 916.7436 rev/min

3 0
4 years ago
Can someone answer these?
natita [175]

Short Answer

3: C

4: D

Problem Three

Remark

Somewhere we ought to be told that this is the Doppler Effect. I have never done a problem using this formula, so I think I'm doing it correctly, but no guarantees. My guess is that the frequency increases as it comes towards you and decreases as it moves away from you. I think that is correct.

Formula

<em><u>Givens</u></em>

  • f' = observed frequency
  • f = actual frequency
  • v = velocity of sound or light waves.
  • vo = velocity of observer (in both cases 0)
  • vs = velocity of source.

f' = (v + vo) * f / (v - vs)

Solution

  • v = 3*10^8 m/s
  • f' = 1.1 f
  • f = f
  • vo = 0  We are standing still while all this is going on.
  • vs = ???

f'/f = 1.1

1.1 = (3*10^8  + 0 ) / (3*10^8 - vs)

3.3*10^8 - 1.1*vs = 3*10^8

3.3*10^8 - 3*10^8= 1.1 vs

0.3 * 10^8 = 1.1 vs

2.73 * 10^7 = vs

The closest answer is 3.00 * 10^7 which is C

Problem Four

Here what is happening is that you are looking for the frequency resulting from a wave moving towards you at 1/2 the speed of sound. You are not moving.

<em><u>Givens</u></em>

  • v = v
  • vs = 1/2 v
  • f ' = ?
  • f = 1000 hz
  • vo =0

f' = v/(v - 1/2v) * 1000

f' = v/ (1/2 v) * 1000

f' = 2 * 1000

f' = 2000 which is D

4 0
4 years ago
Calculate the equivalent resistance for both circuits.
Allisa [31]

Answer:

Series equivalent resistance: R_{eq} = 6  \Omega

Parallel equivalent resistance: R_{eq}=14\Omega

Explanation:

The equivalent resistance in series circuit is calculated as

R_{eq} = R_{1} + R_{2}

R_{eq} = 2 + 4

R_{eq} = 6  \Omega

The equivalent resistance in parallel circuit is calculated as

\frac{1}{R_{eq}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}

Which can be simplified to

R_{eq}=\frac{R_{1}\times R_{2}}{R_{1}+R_{2}}

R_{eq}=\frac{21\times 42}{21+42}

R_{eq}=14\Omega

The parallel circuit has the higher equivalent resistance as compared to series circuit.

5 0
4 years ago
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