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2 years ago

NEED HELP!!! WILL GIVE 15 POINTS!!! PLEASE HELP!!!

Mathematics

1 answer:

nikklg [1K]2 years ago

7 0

Answer:

Square area=100 unit²

Circle area=314 unit²

Step-by-step explanation:

The area of the square=S²

${10}^{2} = 100 \: units \: squared$

The area of the circle=πr²

$\pi {10}^{2} = 3.14 \times {10}^{2} = 314 \: units \: squared$

The difference in the two areas=314–100=214

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2 years ago

The perimeter of a rectangle is 28 cm and its length is 8 cm. Find its breadth.

Yakvenalex [24]

Answer:
The width of the rectangle is 6cm.

Explanation:
Perimeter=2(length+width)
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3 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

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2 years ago

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artcher [175]

Answer:

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Step-by-step explanation:

We can factor the expression by using the common factor.

Pull out 3x from the expression.

$3x - 9 {x}^{2} \\ 3x(1 - 3x)$

Common Factor is similar to dividing by the term we pull out. When we pull out the term, we divide the whole expression and keep the term out of the expression.

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3 years ago