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irinina [24]
3 years ago
8

How many moles are in 25.2g of KMnO4?

Chemistry
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

The answer is: 0.159 moles of KMnO4

Explanation:

Hello!

Let's solve this!

To calculate the mole quantity we need to know the mass of the compound.

In this case the mass is:

We add the mass of each of the compounds:

158,034 g / mol

As data we have 25.2g so we calculate:

moles of KMnO4 = 25.2g * (1mol / 158.034g) = 0.159 moles

The answer is: 0.159 moles of KMnO4

Zolol [24]3 years ago
4 0
When finding the moles in a compound you have to know the grams. In this case, 25.2 grams are given for KMnO4. To find the moles you would divide the amount of grams by the molar mass of KMnO4. The molar mass of KmnO4 is 158.034. You you would now divide 25.2 by 158.034 which is 0.15946 moles. Depending on how many decimal places the questions asks for is dependent on you. I just went with 5 significant figures. 
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Answer:

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Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

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