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irinina [24]
3 years ago
8

How many moles are in 25.2g of KMnO4?

Chemistry
2 answers:
tresset_1 [31]3 years ago
8 0

Answer:

The answer is: 0.159 moles of KMnO4

Explanation:

Hello!

Let's solve this!

To calculate the mole quantity we need to know the mass of the compound.

In this case the mass is:

We add the mass of each of the compounds:

158,034 g / mol

As data we have 25.2g so we calculate:

moles of KMnO4 = 25.2g * (1mol / 158.034g) = 0.159 moles

The answer is: 0.159 moles of KMnO4

Zolol [24]3 years ago
4 0
When finding the moles in a compound you have to know the grams. In this case, 25.2 grams are given for KMnO4. To find the moles you would divide the amount of grams by the molar mass of KMnO4. The molar mass of KmnO4 is 158.034. You you would now divide 25.2 by 158.034 which is 0.15946 moles. Depending on how many decimal places the questions asks for is dependent on you. I just went with 5 significant figures. 
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Explanation:

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Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

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The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

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