At the boiling point, the vapor pressure of a liquid is equal to the atmospheric pressure.
Frequency is defined as the number of waves per second. In this machine 25 waves pass in one second.
We need to calculate the number of waves that pass a particular point during one second.
During 2 seconds -25 waves
Therefore in one second - 25/2 = 12.5 waves/s.
1 wave per second has the unit Hertz (Hz)
Therefore answer is 12.5 Hz
Answer:
The answer to your question is Q = 18702.5 J
Explanation:
Data
mass of water = m = 447 g
Cp = 4.184 J/g°C
Temperature 1 = T1 = 25°C
Temperature 2 = T2 = 35°C
Heat = Q = ? Joules
Process
1.- Write the formula to calculate heat
Q = mCp(T2 - T1)
2.- Substitution
Q = (447)(4.184)(35 - 25)
3.- Simplification
Q = (447)(4.184)(10)
4.- Result
Q = 18702.5 J
Answer:
The pressure inside the container is 6.7 atm
Explanation:
We have the ideal gas equation: P x V = n x R x T
whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)
Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.
So we can calculate the pressure by
P = n x R x T / V
where as,
n = 41.1 g / 44 g/mol = 0.934 mol
Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm
