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devlian [24]
3 years ago
7

.​Find the pH if the [H3O+1] is 6.2  10-10 M

Chemistry
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

The pH is 9,21.

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and higher than 7 to 14 basic. It is calculated as

pH = -log (H 30+)

pH= -log (6,2 x 10^-10)

<em>pH=9,21</em>

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During surgery, a patient receives 3.5 pt of plasma. How many milliliters of plasma were given?
Readme [11.4K]

Answer:

1656.116

Explanation:

473.176 is how many millimetres equals a pint and you would multiply that by 3.5

4 0
3 years ago
What is the H+ ion concentration of a solution with a pH of 7?
wariber [46]

Answer:

10-7mol/l

Explanation:

7 0
3 years ago
Read 2 more answers
Precipitation reactions always occur when two aqueous solutions are mixed (T/F)
Studentka2010 [4]

Answer: The given statement is false.

Explanation:

Precipitation reaction is defined as the chemical reaction in which two aqueous solution upon mixing together results in the formation of an insoluble solid.

For example, NaCl(aq) + AgNO_{3} \rightarrow NaNO_{3}(aq) + AgCl(s)

Here AgCl is present in solid state so, it is the precipitate.

But it is not necessarily true that two aqueous solutions will always result in the formation of a precipitate.

For example, NaCl(aq) + KNO_{3}(aq) \rightarrow KCl(aq) + NaNO_{3}(aq)

Hence, we can conclude that the statement precipitation reactions always occur when two aqueous solutions are mixed, is false.

7 0
3 years ago
Purification of copper can be achieved by electrorefining copper from an impure copper anode onto a pure copper cathode in an el
Dovator [93]

Answer: 406 hours

Explanation:

Q=I\times t

where Q= quantity of electricity in coloumbs

I = current in amperes = 39.5 A

t= time in seconds = ?

The deposition of copper at cathode is represented by:

Cu^{2+}+2e^-\rightarrow Cu

96500\times 2=193000 Coloumb of electricity deposits 1 mole of copper

i.e. 63.5 g of copper is deposited by = 193000 Coloumb

Thus 19.0 kg or 19000 g of copper is deposited by = \frac{193000}{63.5}\times 19000=57748032 Coloumb

57748032=39.5\times t

t=1461975sec=406hours    (1hour=3600s)

Thus it will take 406 hours to plate 19.0 kg of copper onto the cathode if the current passed through the cell is held constant at 39.5 A

3 0
3 years ago
What is the mass of oxygen in 3.34 g of potassium permanganate?
3241004551 [841]

Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

So,

Molar Mass of KMnO₄ = 39 + 55 + 4(16)

Molar Mass of KMnO₄ = 158 g/mol

Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

                  mass of Oxygen (O) = 0.405 x 3.34 g

                  mass of Oxygen (O) = 1.35 g

5 0
3 years ago
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