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3 years ago

Ok bye guys going offline have a great daydefine metabolism

Engineering

2 answers:

Rus_ich [418]3 years ago

6 0

Answer:

the chemical processes in plants or animals that change food into energy and help them grow

पेड़-पौधों और जंतुओं में होने वाली रासायनिक प्रक्रियाएँ जो भोजन को ऊर्जा में परिवर्तित कर देती हैं जिससे उनकी वृद्धि होती है; चयापचयन, उपाप्चय

Explanation:

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IgorLugansk [536]3 years ago

6 0

Metabolism (pronounced: meh-TAB-uh-liz-um) is the chemical reactions in the body's cells that change food into energy. Our bodies need this energy to do everything from moving to thinking to growing. Specific proteins in the body control the chemical reactions of metabolism.

Explanation:

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what is the transfer function of the loaded filter? express your answer in terms of the variables r , l , rl , and s .

NISA [10]

Loaded, $H_{Loaded}$ (s) = $\frac{RR_{L} }{R+R_{L} } /(\frac{RR_{L} }{R+R_{L} }+SL)$ = $\frac{RR_{L}/L }{R+R_{L} } /(\frac{RR_{L} /L}{R+R_{L} }+S)$ is the loaded filter's transfer function.

A graded filter that, by virtue of its weight and permeability, stabilises the foot of an earth dam or other construction when it is installed at the base of that structure.

Air filters with depth loaded are made to achieve precisely that. They add particles gradually to create air passageways, reducing constriction. You may save time and money by using filters that last longer thanks to them. The bigger particles are caught at the filter's beginning, while the smaller particles are caught as it gets closer. This is intended to avoid rapid surface loading, hence facilitating more airflow. This enables longer-lasting filtration as well.

On the other hand, surface loading filters catch every particle that is on its surface. No matter how big or little the particles are, it doesn't care.

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KIM [24]

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3 years ago

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3 years ago

Read 2 more answers

Determine the resistance values for a voltage divider that must meet the following specifications:_______.

Nikolay [14]

Answer:

i) when circuit is unloaded : R1 + R2 = 2kΩ.

ii) when 5V output voltage is applied : R1 = 1 kΩ , R2 = 1 kΩ

iii) when 2.5 v output voltage is applied : R1 = 1500 Ω, R2 = 500 Ω

iv) when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

Explanation:

Current drawn from source under loaded condition ≤ 5 mA

source voltage = 10 v , required output = 5 v , 2.5 v

attached below is the sketch of the circuit

Resistance values

i) when the circuit is unloaded

Req = R1 + R2 = 2 kΩ ( Req = Vs / I = 10 / 5*10^-3 = 2 kΩ )

ii) when output voltage = 5 v

we will apply voltage divider rule

R1 = 1 kΩ ,

R2 = 1 kΩ

iii) When the output voltage = 2.5 v

applying voltage divider rule

R1 = 1500 Ω

R2 = 500 Ω

iv) when the load is connected to each tap one at a time

i.e. when the resistance are in parallel

when: R1 = 1 kΩ , R2 = 1 kΩ is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

attached below is the detailed solution to the given problem

8 0

3 years ago

Ok bye guys going offline have a great daydefine metabolism​

Ok bye guys going offline have a great daydefine metabolism