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Oksanka [162]
3 years ago
13

Ok bye guys going offline have a great daydefine metabolism​

Engineering
2 answers:
Rus_ich [418]3 years ago
6 0

Answer:

the chemical processes in plants or animals that change food into energy and help them grow

पेड़-पौधों और जंतुओं में होने वाली रासायनिक प्रक्रियाएँ जो भोजन को ऊर्जा में परिवर्तित कर देती हैं जिससे उनकी वृद्धि होती है; चयापचयन, उपाप्चय

Explanation:

plz mark me as brainiest

IgorLugansk [536]3 years ago
6 0

Metabolism (pronounced: meh-TAB-uh-liz-um) is the chemical reactions in the body's cells that change food into energy. Our bodies need this energy to do everything from moving to thinking to growing. Specific proteins in the body control the chemical reactions of metabolism.

Explanation:

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>helpful</em><em> </em><em>for</em><em> </em><em>you</em><em> </em></h2><h2><em>keep</em><em> </em><em>always</em><em> </em><em>smiling</em><em> </em></h2>
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what is the transfer function of the loaded filter? express your answer in terms of the variables r , l , rl , and s .
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Loaded, H_{Loaded}(s) = \frac{RR_{L} }{R+R_{L} } /(\frac{RR_{L} }{R+R_{L} }+SL) = \frac{RR_{L}/L }{R+R_{L} } /(\frac{RR_{L} /L}{R+R_{L} }+S) is the loaded filter's transfer function.

A graded filter that, by virtue of its weight and permeability, stabilises the foot of an earth dam or other construction when it is installed at the base of that structure.

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On the other hand, surface loading filters catch every particle that is on its surface. No matter how big or little the particles are, it doesn't care.

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Find the solution in the attachments

Note: Question was incomplete, so the complete question is added in the attachments.

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Read 2 more answers
Determine the resistance values for a voltage divider that must meet the following specifications:_______.
Nikolay [14]

Answer:

i) when circuit is unloaded : R1 + R2 = 2kΩ.

ii) when 5V output voltage is applied :  R1 = 1 kΩ , R2 =  1 kΩ

iii) when 2.5 v output voltage is applied : R1 = 1500 Ω,  R2 = 500 Ω

iv) when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

Explanation:

Current drawn from source under loaded condition ≤ 5 mA

source voltage = 10 v ,  required output = 5 v , 2.5 v

attached below is the sketch of the circuit

Resistance values

<em>i) when the circuit is unloaded </em>

Req = R1 + R2 = 2 kΩ  ( Req = Vs / I  = 10 / 5*10^-3 = 2 kΩ )

<em>ii) when  output voltage = 5 v</em>

we will apply voltage divider rule

R1 = 1 kΩ ,

R2 =  1 kΩ

<em>iii) When the output voltage = 2.5 v </em>

applying voltage divider rule

R1 = 1500 Ω

R2 = 500 Ω

iv) when the load is connected to each tap one at a time

i.e. when the resistance are in parallel

when: R1 = 1 kΩ , R2 =  1 kΩ  is connected in parallel output voltage < 5 V

When : R1 = 1500 Ω, R2 = 500 Ω is connected in parallel output voltage > 2.5V

attached below is the detailed solution to the given problem

8 0
3 years ago
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