Answer:
i) 796.18 N/mm^2
ii) 1111.11 N/mm^2
Explanation:
Initial diameter ( D ) = 12 mm
Gage Length = 50 mm
maximum load ( P ) = 90 KN
Fractures at = 70 KN
minimum diameter at fracture = 10mm
<u>Calculate the engineering stress at Maximum load and the True fracture stress</u>
<em>i) Engineering stress at maximum load = P/ A </em>
= P / = 90 * 10^3 / ( 3.14 * 12^2 ) / 4
= 90,000 / 113.04 = 796.18 N/mm^2
<em>ii) True Fracture stress = P/A </em>
= 90 * 10^3 / ( 3.24 * 10^2) / 4
= 90000 / 81 = 1111.11 N/mm^2
Answer:
The answer for the question is true
Explanation:
If you get a virus or get hacked you will still have it saved
Answer:
V₅ = 20 V
Explanation:
Given that
Total voltage ,V= 120 V
Given that resistor are connected in series that is why the total voltage drop will be summation of voltage drop in the all resistor.
V₁=Voltage drop on first resistor
V₂=Voltage drop on second resistor
V₃=Voltage drop on third resistor
V₄=Voltage drop on forth resistor
V₅=Voltage drop on fifth resistor
Therefore
V= V₁+V₂+V₃+V₄+V₅
120 = 35 + 28 + 22 + 15 + V₅
V₅ = 20 V
Therefore the voltage drop on the fifth resistor will be 20 V.
Answer:
A) β_max = 20.64
B) TH = 68.25°C
C) TC = 54.27°C
Explanation:
A) We are given;
TH = 16°C = 16 + 273K = 289K
TC = 2°C = 2 + 273K = 275K
Formula for maximum cycle coefficient of performance is given as;
β_max = TH/(TH - TC)
β_max = 289/(288 - 275)
β_max = 20.64
B) We are given;
Heat rejected to system at hot reservoir; Q_H = 10.5 KW
Heat provided to system at cold reservoir; Q_C = 8.75 KW
Cold reservoir temperature; TC = 0°C = 0 + 273K = 273K
Formula for actual cycle COP is given as;
β_actual = Q_C/W_cycle
Where W_cycle is the work done and is given by;
W_cycle = Q_H - Q_C
W_cycle = 10.5 - 8.75 = 1.75 KW
Thus,
β_actual = 8.75/1.75
β_actual = 5
Actual cycle COP is defined as;
β_actual = TH/(TH - TC)
And we are looking for TH.
Thus,
TH = TC/(1 - (1/β_actual))
TH = 273/(1 - 1/5)
TH = 273/(4/5)
TH = 341.25K = 341.25 - 273°C = 68.25°C
C) We are given;
TH = 27°C = 27 + 273 = 300°C
β_max = 12
Thus, from,
β_max = TH/(TH - TC)
TC = TH(1 - (1/β_max))
TC = 300/(1 - 1/12)
TC = 327.27K = 327.27 - 273 °C = 54.27°C
Answer:
The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm
Explanation:
uncertainty in a nominal displacement
= (u^2 + v^2)^(1/2)
assume from specifications that k = 5v/5cm
= 1v/cm
u^2 = (0.0025*2)^(2) + (0.005*10*2)^2 + (0.0025*2)^2
= 0.01225v
v = 2v * 0.001
= 0.002v
uncertainty in a nominal displacement
= (u^2 + v^2)^(1/2)
= ((0.01225)^2 + (0.002)^2)^(1/2)
= 0.0124 cm
Therefore, The Estimated uncertainty in a nominal displacement of 2 cm at the design stage is plus or minus 0.0124cm