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luda_lava [24]
3 years ago
8

A 3-phase induction motor is being driven at a frequency of 80 Hz, and the motor speed is 1000 rpm. How many poles does the moto

r probably have and what is the slip? (10 points)
Engineering
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

8 poles

Slip= 16.67%

Explanation:

We use the formula for synchronous speed, N_s=\frac {120 f}{p}

Where f is the frequency and p is the number of poles

Since frequency is given as 80 Hz and the motor speed also given as 1000 rpm then making p the subject of the above formula we get

p=\frac {120 f}{N_s}

By substitution

p=\frac {120 \times 80}{1000}=9.6\approx 8 poles

To find the slip, we now use the actual N_s and since we know that N_s=\frac {120 f}{p} and p=8 then

N_s=\frac {120 \times 80}{8}=1200

The motor speed is now N_r=1000 rpm

To find slip, we use the formula

Slip=\frac {N_s- N_r}{N_s} \times 100

Then by substitution

Slip=\frac {1200-1000}{1200}\times 100=0.166666667\times 100\approx 16.67

Therefore, slip=16.67%

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If the bolt head and the supporting bracket are made of the same material having a failure shear stress of 'Tra;i = 120 MPa, det
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Answer:

P=361.91 KN

Explanation:

given data:

brackets and head of the screw are made of material with T_fail=120 Mpa

safety factor is F.S=2.5

maximum value of force P=??

<em>solution:</em>

to find the shear stress

                            T_allow=T_fail/F.S

                                         =120 Mpa/2.5

                                         =48 Mpa

we know that,

                               V=P

<u>Area for shear head:</u>

                              A(head)=π×d×t

                                           =π×0.04×0.075

                                           =0.003×πm^2

<u>Area for plate:</u>

                               A(plate)=π×d×t  

                                            =π×0.08×0.03

                                            =0.0024×πm^2

now we have to find shear stress for both head and plate

<u>For head:</u>

                                   T_allow=V/A(head)

                                    48 Mpa=P/0.003×π                 ..(V=P)

                                             P =48 Mpa×0.003×π

                                                =452.16 KN

<u>For plate:</u>

                                   T_allow=V/A(plate)

                                    48 Mpa=P/0.0024×π                 ..(V=P)

                                             P =48 Mpa×0.0024×π

                                                =361.91 KN

the boundary load is obtained as the minimum value of force P for all three cases. so the solution is

                                                P=361.91 KN

note:

find the attached pic

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