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luda_lava [24]
3 years ago
8

A 3-phase induction motor is being driven at a frequency of 80 Hz, and the motor speed is 1000 rpm. How many poles does the moto

r probably have and what is the slip? (10 points)
Engineering
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

8 poles

Slip= 16.67%

Explanation:

We use the formula for synchronous speed, N_s=\frac {120 f}{p}

Where f is the frequency and p is the number of poles

Since frequency is given as 80 Hz and the motor speed also given as 1000 rpm then making p the subject of the above formula we get

p=\frac {120 f}{N_s}

By substitution

p=\frac {120 \times 80}{1000}=9.6\approx 8 poles

To find the slip, we now use the actual N_s and since we know that N_s=\frac {120 f}{p} and p=8 then

N_s=\frac {120 \times 80}{8}=1200

The motor speed is now N_r=1000 rpm

To find slip, we use the formula

Slip=\frac {N_s- N_r}{N_s} \times 100

Then by substitution

Slip=\frac {1200-1000}{1200}\times 100=0.166666667\times 100\approx 16.67

Therefore, slip=16.67%

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The device whose operation closely matches the way the clamp-on ammeter works is
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The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6*g, respectively.
ehidna [41]

Answer:

The speed of shaft is 1891.62 RPM.

Explanation:

given that

Amplitude A= 0.15 mm

Acceleration = 0.6 g

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we can say that acceleration= 0.6 x 9.81

acceleration,a=5.88\ \frac{m}{s^2}

We know that

a=\omega ^2A

So now by putting the values

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198.0=2πN/60

N=1891.62 RPM

So the speed of shaft is 1891.62 RPM.

                                               

       

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