Estimate the uncertainty in a 22 m/sec air velocity measurement using a Pitot tube at 20C. Assume the atmospheric pressure is 1
00 kPa and that R and the density of water, H O2 are known with high enough accuracy to consider them as constants (zero uncertainty). The pressure for each tap is measured with separate manometers that have a resolution of 0.5 mm. The manometers use water as the fluid and each are oriented vertically. The absolute pressure (which gives you the density of air) is known with an uncertainty of 0.1 kPa. The temperature is known with an uncertainty of 1C. Assume the stagnation pressure, pt, is indicated by a static height of 7 mm.
1 answer:
Answer:
Check the explanation
Explanation:
In calculating the second version of velocity that is expected velocity, which involves the division of the overall amount of estimated story points by the amount of sprints. Take for instance, if the development team estimates a total of 150 points over five sprints, then we can say that the team's expected velocity would be 30 points per sprint.
Kindly check the attached image below to see the step by step explanation to the question above.
You might be interested in
Answer:
Explanation:
Let assume that heating and boiling process occurs under an athmospheric pressure of 101.325 kPa. The heat needed to boil water is:
The heat liberated by the LP gas is:
A kilogram of LP gas has a minimum combustion power of . Then, the required mass is:
Answer:
40.8%
Explanation:
A rankine cycle is a generation cycle using water as a working fluid, when heat enters the boiler the water undergoes a series of changes in state and energy until generating power through the turbine.
This cycle is composed of four main components, the boiler, the pump, the turbine and the condenser as shown in the attached image
To solve any problem regarding the rankine cycle, enthalpies in all states must be calculated using the thermodynamic tables and taking into account the following.
• The pressure of state 1 and 4 are equal
• The pressure of state 2 and 3 are equal
• State 1 is superheated steam
• State 2 is in saturation state
• State 3 is saturated liquid at the lowest pressure
• State 4 is equal to state 3 because the work of the pump is negligible.
Once all enthalpies are found, the following equations are used using the first law of thermodynamics
Wout = m (h1-h2)
Qin = m (h1-h4)
Win = m (h4-h3)
Qout = m (h2-h1)
The efficiency is calculated as the power obtained on the heat that enters
Efficiency = Wout / Qin
Efficiency = (h1-h2) / (h1-h4)
first we calculate the enthalpies in all states
h1=3386kJ/Kg
h2=2073kJ/Kg
h2=h3=167.5kJ/Kg
we use the efficiency ecuation
Answer:
The equation used to solve a diode is
is the current going through the diode
is your saturation current
is the voltage across your diode
is the voltage of the diode at a certain room temperature. by default, you always use
for room temperature.
If you look at the equation, , you'd notice that the
grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.
Therefore, use to solve your equation.
Rearrange your equation to solve for .
a.)
i.)
You're given
at ,
at ,
at ,
<em>note: always use</em>
ii.)
Just repeat part (i) but change to
b.)
same process as part A. You do the rest of the problem by yourself.