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erastova [34]
2 years ago
14

The velocity profile for a thin film of a Newtonian fluid that is confined between the plate and a fixed surface is defined by u

= (5y-0.5y2) mm/s where y is in mm. Determine the force P that must be applied to the plate to cause this motion. The plate has a surface area of 4000mm2 in contact with the fluid. Take µ= 0.55 N.s/m2
Engineering
1 answer:
zimovet [89]2 years ago
8 0

Answer:

F = 0.0022N

Explanation:

Given:

Surface area (A) = 4,000mm² = 0.004m²

Viscosity = µ = 0.55 N.s/m²

u = (5y-0.5y²) mm/s

Assume y = 4

Computation:

F/A = µ(du/dy)

F = µA(du/dy)

F = µA[(d/dy)(5y-0.5y²)]

F = (0.55)(0.004)[(5-1(4))]

F = 0.0022N

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Read 2 more answers
PLEASE HELP QUICK!!
ivolga24 [154]

R01= 14.1 Ω

R02=  0.03525Ω

<h3>Calculations and Parameters</h3>

Given:

K= E2/E1 = 120/2400

= 0.5

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R2= 0.035Ω, X2= 0.012Ω

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