Question

For a certain spring, k = 15N/m. A weight is hung from the spring, stretching it from 0.3m to 0.4m. What force did the weight produce
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Answer 1

The stretch of the spring is
$\Delta x = 0.4 m-0.3 m=0.1 m$
The constant of the spring is k=15 N/m, so we can find the force produced by the weight by using Hook's law:
$F=k\Delta x=(15 N/m)(0.1 m)=1.5 N$