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VladimirAG [237]
3 years ago
13

How do animals affect the amount of carbon in earth’s atmosphere

Physics
1 answer:
Sedbober [7]3 years ago
8 0
Some animals release greenhouse gases (cows fart) which produce an excessive amount of carbon into the air (BAD!)
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A pitcher throws a 0.14-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just
kykrilka [37]

Answer

given,

mass of base ball = 0.14 kg

speed before it made the contact with the ball (V i) = 42 m/s

speed after batter hit the ball(V f) = - 48 m/s

a)                                            

impulse = change in momentum

             = m\times (V_f-V_i)      

             =0.14\times (-48-42)

             = -12.6 Kg m/s

Magnitude of impulse = 12.6 Kg m/s

b)                                                        

Force = \dfrac{impulse}{time}

          =  \dfrac{12.6}{0.005}

Force = 2520 N

5 0
3 years ago
A bus travelling 30.0 km/h east has a constant increase in speed of 1.5 m/s. What is its velocity 6.8s later
alekssr [168]

Answer:

8.72 seconds before

Explanation:

and 27.1 secs after

7 0
3 years ago
Convection occurs when thermal energy is transferred by the movement of
madam [21]

Answer:

Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.

6 0
2 years ago
A 2kg bowling ball rolls at a speed of 5 m/s on a roof of the building that is 40 meters tall. What is the kinetic energy
MrRa [10]
The kinetic energy is \frac 1 2 m v^2 and the height of the building doesn't matter at all.

E = \frac 1 2 m v^2 = \frac 1 2 (2)(5)^2 = 25 joules
 
8 0
2 years ago
You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same s
densk [106]

Here when car in front of us applied brakes then it is slowing down due to frictional force on it

So here we can say that friction force on the car front of our car is given as

F_f = \mu m g

So the acceleration of car due to friction is given as

F_{net} = - \mu mg

a = \frac{F_{net}}{m}

a = -\mu g

now it is given that

\mu = 0.868

g = 9.81 m/s^2

so here we have

a = -0.868 * 9.81

a = -8.52 m/s^2

so the car will accelerate due to brakes by a = - 8.52 m/s^2

4 0
3 years ago
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