Answer:
Distance of the point where electric filed is 2.45 N/C is 1.06 m
Explanation:
We have given charge per unit length, that is liner charge density 
Electric field E = 2.45 N/C
We have to find the distance at which electric field is 2.45 N/C
We know that electric field due to linear charge is equal to
, here 
is linear charge density and r is distance of the point where we have to find the electric field
So 
r = 1.06 m
So distance of the point where electric filed is 2.45 N/C is 1.06 m
Answer:
0.5 m/s2
Explanation:
accelration formula : final velocty - starting velocity divided by time
The statement “Electrons are pulled closer to the oxygen
atom” correctly describes the electrons in a water molecule. The
correct answer between all the choices given is the second choice or letter B. I
am hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.
Whatever distance north and then west you walked, you are then
(1.41 x that distance)
northwest of where you started.
Radius of nuclei is given by formula
now we can say volume of the nuclei is given as
now the density is given as
density = mass / volume
mass of nuclei = mass of neutron + mass of protons
Now density is given as
here we know that
= 1.2 fm
So from above we can say that density of all nuclei is almost same.
