Answer:
R=2F
Explanation:
As the forces are in same direction so the resultant force will be:
R=F+F
R=2F
![{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\](https://tex.z-dn.net/?f=%7B%5Cmathfrak%7B%5Cunderline%7B%5Cpurple%7B%5C%3A%5C%3A%5C%3A%20Given%3A-%5C%3A%5C%3A%5C%3A%7D%7D%7D%7D%20%5C%5C%20%5C%5C)
![\:\:\:\:\bullet\:\:\:\sf{Focal\:length=10\:cm}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5Cbullet%5C%3A%5C%3A%5C%3A%5Csf%7BFocal%5C%3Alength%3D10%5C%3Acm%7D)
![\:\:\:\:\bullet\:\:\:\sf{Object \ distance = -15\:cm}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5Cbullet%5C%3A%5C%3A%5C%3A%5Csf%7BObject%20%5C%20distance%20%3D%20-15%5C%3Acm%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\](https://tex.z-dn.net/?f=%7B%5Cmathfrak%7B%5Cunderline%7B%5Cpurple%7B%5C%3A%5C%3A%5C%3ATo%20%5C%3AFind%3A-%5C%3A%5C%3A%5C%3A%7D%7D%7D%7D%20%5C%5C%20%5C%5C)
![\:\:\:\:\bullet\:\:\:\sf{Nature \: of \:the\:image}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5Cbullet%5C%3A%5C%3A%5C%3A%5Csf%7BNature%20%5C%3A%20of%20%5C%3Athe%5C%3Aimage%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![{\mathfrak{\underline{\purple{\:\:\: Solution:-\:\:\:}}}} \\ \\](https://tex.z-dn.net/?f=%7B%5Cmathfrak%7B%5Cunderline%7B%5Cpurple%7B%5C%3A%5C%3A%5C%3A%20Solution%3A-%5C%3A%5C%3A%5C%3A%7D%7D%7D%7D%20%5C%5C%20%5C%5C)
<h3>☯ <u>By using formula of Lens</u> </h3>
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{\dfrac{1}{v}-\dfrac{1}{-15}=\dfrac{1}{10}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7B%5Cdfrac%7B1%7D%7Bv%7D-%5Cdfrac%7B1%7D%7B-15%7D%3D%5Cdfrac%7B1%7D%7B10%7D%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{\dfrac{1}{v}+\dfrac{1}{15}=\dfrac{1}{10}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7B%5Cdfrac%7B1%7D%7Bv%7D%2B%5Cdfrac%7B1%7D%7B15%7D%3D%5Cdfrac%7B1%7D%7B10%7D%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{15}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7B%5Cdfrac%7B1%7D%7Bv%7D%20%3D%20%5Cdfrac%7B1%7D%7B10%7D%20-%20%5Cdfrac%7B1%7D%7B15%7D%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{ v = 30 \ cm}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7B%20v%20%3D%2030%20%5C%20cm%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
<h3>☯ <u>Now, Finding the magnification </u></h3>
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{ m = \dfrac{-30}{-15}}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7B%20m%20%3D%20%5Cdfrac%7B-30%7D%7B-15%7D%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
![\dashrightarrow\:\: \sf{m = -2}](https://tex.z-dn.net/?f=%5Cdashrightarrow%5C%3A%5C%3A%20%5Csf%7Bm%20%3D%20-2%7D)
![\\](https://tex.z-dn.net/?f=%5C%5C)
<h3>☯ <u>Hence</u>,
![\\](https://tex.z-dn.net/?f=%5C%5C)
</h3>
![\:\:\:\:\star\:\:\:\sf{Image \ distance = 30 \ cm}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5Cstar%5C%3A%5C%3A%5C%3A%5Csf%7BImage%20%5C%20distance%20%3D%2030%20%5C%20cm%7D)
![\:\:\:\:\star\:\:\:\sf{Nature = Real \ \& \ inverted}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5Cstar%5C%3A%5C%3A%5C%3A%5Csf%7BNature%20%3D%20Real%20%5C%20%5C%26%20%5C%20inverted%7D)
Answer:
200 km\h
or 0.621 mp\h its the same speed just different mesuarements