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VikaD [51]
3 years ago
12

What do low energy waves have

Physics
1 answer:
Elena-2011 [213]3 years ago
7 0
The Answer: Photons

There is photons in low energy waves
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The velocity of any object depends upon
const2013 [10]
The displacement, time, and direction
5 0
3 years ago
Read 2 more answers
What is the amount of heat, in Sl units, necessary to melt 1 lb of ice?
likoan [24]

Answer:

Heat required to melt 1 lb of ice is 151.469 KJ

Explanation:

We have given mass of ice = 1 lb

We know that 1 lb = 0.4535 kg

Latent heat of fusion for ice =334 KJ/kg

Amount if heat for fusion of ice is given by

Q=mL, here m is mass of ice and L is latent heat of fusion

So heat Q=mL=0.4535\times 334=151.469kj

So heat required to melt 1 lb of ice is equal to 151.469 KJ

3 0
4 years ago
Fill in the appropriate values for each blank as it refers to ATOM 1. The number of protons present in ATOM 1 is _________.​
wlad13 [49]
3, protons are positive and there are 3 positive atoms visible
6 0
4 years ago
Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.
Nina [5.8K]

The resultant of the two forces is about 170 N.

<h3>What is the resultant force?</h3>

The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.

In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N  + 80 N = 170 N.

Learn more about resultant force:brainly.com/question/16380983

#SPJ1

5 0
2 years ago
Please show work : A particle with mass 2.00 μg and a charge of – 200 nC has a velocity of 3000 m/s in the x-direction. There is
irga5000 [103]

Answer:

 x =4.5 10⁴ m

Explanation:

To find the distance that the particle moves we must use the equations of motion in one dimension and to find the acceleration of the particle we will use Newton's second law

     m = 2.00 mg (1 g / 1000 ug) (1 Kg / 1000g) = 2.00 10-6 Kg

     q = -200 nc (1C / 10 9 nC) = -200 10-9 C

Let's calculate the acceleration

     F = ma

     F = q E

     a = qE / m

     a = -200 10⁻⁹ 1000 / 2.00 10⁻⁶

     a = 1 10² m / s²

Let's use kinematics to find the distance traveled before stopping, where it has zero speed (Vf = 0)

     Vf² = Vo² -2 a x

     0 = Vo² - 2 a x

     x = Vo² / 2a

     x = 3000²/ 2100

     x =4.5 10⁴ m

This is the distance the particule stop, after this distance in the field accelerates in the opposite direction of the initial

Second part

In this case Newton's second law is applied on the y axis

      F -W = 0

      F = w = mg

      E q = mg

      E = mg / q

      E = 2.00 10⁻⁶ 9.8 / 200 10⁻⁹

      E = 9.8 10⁵ C

       

The direction of the field is such that the force on the particle is up, as the particle has a negative charge, the field must be directed downwards F = qE = (-q) E

7 0
4 years ago
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