Which of the following is not a unit used to measure pressure?

Physics

2 answers:

Luden [163]3 years ago

7 0

Newtons are used to measure force

Ilya [14]3 years ago

4 0

Answer:

The answer is Newton.

Explanation:

In order to determine the unit that it is not used to measure pressure, we have to define the units for every option and then compare them.

Torr (symbol: Torr): is a unit of pressure based on an absolute scale, now defined as exactly 1/760 of a standard atmosphere (≈ 133.32 Pa).

Newton (symbol: N) is the International System of Units (SI) derived unit of force.

Atmosphere (symbol: atm): the standard atmosphere is a unit of pressure defined as 101325 Pa (1.013 bar)

Milimeter of mercury (symbol: mmHg): is a manometric unit of pressure, formerly defined as the extra pressure generated by a column of mercury one millimetre high, and currently defined as exactly 133.32 Pa.

Therefore, the physics unit that not represent a pressure measure is Newton.

You might be interested in

A ball of mass 2 kg is kept on the hill of height 3 km. Calculate the potential energy possessed by it ?

zysi [14]

We know that -

$P.E=m*g*h$

Where,

$m = mass$

$g = acceleration$ $due$ $to$ $gravity$

$h=height$

First we convert height into meters.

1 km = 1000 meters

3 km = 1000 * 3 meters = 3000 meters

So, putting the values in the above formula, and by taking 'g' = 9.8 m/s², we get-

$P.E.= 2*3000*9.8$

$P.E.= 58800$ $Joules$

$P.E.= 58.8$ $kJ$

7 0

3 years ago

Read 2 more answers

A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a

GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1