Explanation:
(a) According to the law of conservation of energy,
Potential energy = Kinetic energy
mgh =
Putting the given values into the above formula as follows.
mgh =
h = 0.9 m
Therefore, the height H is 0.9 m.
(b) For the given situation,
Kinetic energy = work done by friction
u = 0.3
Thus, we can conclude that the coefficient of kinetic friction on the horizontal surface is 0.3.
Answer:
Range.
Explanation:
Range in projectile motion can be defined as the horizontal distance traveled by an object.
An example of range would be the horizontal distance a soccer ball moves between being kicked and touching the ground again.
Answer:
The distance from the top of the stick would be 2l/3
Explanation:
Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.
Applying impulse momentum theorem for linear momentum.
FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2
Similarly applying impulse momentum theorem per angular momentum about H
FΔt * x = I * W
Where FΔt * x represents the impulsive torque and I is the moment of inertia
F Δt.x = (ml² . W)/3
Substituting FΔt
M(Wl/2) * x = (ml². W)/3
1/x = 3/2l
x = 2l/3
Answer:
-0.4 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the shell + cannon system must be conserved.
Before the shot, the total momentum of the system is zero:
p = 0
After the shot, the total momentum is:
where
m = 3.0 kg is the mass of the shell
v = 200 m/s is the velocity of the shell
M = 1500 kg is the mass of the cannon
V is the recoil velocity of the cannon
Since momentum is conserved, the initial and final momenta must be equal, therefore:
Where the negative sign indicates that the cannon moves in the opposite direction to the shell.