All categories

3 years ago

Which of the following is not a unit used to measure pressure?

Physics

2 answers:

Luden [163]3 years ago

7 0

Newtons are used to measure force

Ilya [14]3 years ago

4 0

Answer:

The answer is Newton.

Explanation:

In order to determine the unit that it is not used to measure pressure, we have to define the units for every option and then compare them.

Torr (symbol: Torr): is a unit of pressure based on an absolute scale, now defined as exactly 1/760 of a standard atmosphere (≈ 133.32 Pa).

Newton (symbol: N) is the International System of Units (SI) derived unit of force.

Atmosphere (symbol: atm): the standard atmosphere is a unit of pressure defined as 101325 Pa (1.013 bar)

Milimeter of mercury (symbol: mmHg): is a manometric unit of pressure, formerly defined as the extra pressure generated by a column of mercury one millimetre high, and currently defined as exactly 133.32 Pa.

Therefore, the physics unit that not represent a pressure measure is Newton.

You might be interested in

The basketball coach tells his team to run sprints back and forth across the court, which is 30 m long. They start at the left e

sp2606 [1]

Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.

The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.

The end point is the same as the starting point, so the displacement is 0 m.

5 0

2 years ago

Please help on this one? PLEASE.

ruslelena [56]

Answer:

A is the answer.........

6 0

3 years ago

How does the centripetal force depend on speed, radius and the revolving mass?

Mnenie [13.5K]

Answer:

Mass velocity and radius are all related to centripetal force

Explanation:

By frequency of its rotation and the radius of the circular path along which objects moves

6 0

2 years ago

What's the degree to which molecules are able to pass through a membrane

lawyer [7]

The degree is 4678% to pass theough all membranes.

8 0

2 years ago

A bowling ball is launched from the top of a building at an angle of 35° above the horizontal with an initial speed of 15 m/s. T

Mamont248 [21]

Let $y_0$ be the height of the building and thus the initial height of the ball. The ball's altitude at time $t$ is given by

$y=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ\,t-\dfrac g2t^2$

where $g=9.80\frac{\rm m}{\mathrm s^2}$ is the acceleration due to gravity.

The ball reaches the ground when $y=0$ after $t=2.9\,\mathrm s$ . Solve for $y_0$ :

$0=y_0+\left(15\dfrac{\rm m}{\rm s}\right)\sin35^\circ(2.9\,\mathrm s)-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(2.9\,\mathrm s)^2$

$\implies y_0\approx16.258\,\mathrm m$

so the building is about 16 m tall (keeping track of significant digits).

3 0

2 years ago