A flea jumps by exerting a force of 1.27 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground
exerts a force of 1.20 10-6 N on the flea. Find the direction and magnitude of the acceleration of the flea if its mass is 6.0 10-7 kg. (Let us assume that Fwind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.)
1 answer:
Since force is a vector quantity, we can find the net force by determining the resultant force. The equation is written below:
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>
F = √(Fx²)+(Fy)²
where
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N
Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²
<em>The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.</em>
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Answer:
E.) conservation of angular momentum
Explanation:
The angular momentum is defined as:
x
where is the radius of the star,
is the mass and
the angular velocity.
and angular momentum is an amount that is conserved, so the angular momentum before the star is compressed must be equal to the angular momentum after the star was compressed:
x
x
the second radius is smaller than the first radius, since the star shrinked, the second angular velocity must be greater that the first.
In other words, the angular velicity increases as the star shrinks because of the conservation of angular momentum.