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algol [13]
3 years ago
7

g power output of 87 W. At what distance will the decibel reading be 120 dB, which is noise level of a loud indoor rock concert

Physics
1 answer:
Kazeer [188]3 years ago
7 0

Given that,

Output power = 87 W

Decibel reading = 120 dB

We need to calculate the intensity of sound

Using formula of intensity of sound

dB=10\log(\dfrac{I}{I_{0}})

Put the value into the formula

120=10\log(\dfrac{I}{1\times10^{-12}})

12=log(\dfrac{I}{1\times10^{-12}})

10^{12}=\dfrac{I}{1\times10^{-12}}

I=10^{12}\times1\times10^{-12}

I=1\ W/m^2

We need to calculate the distance

Using relation of power out[ut and intensity

I=\dfrac{P}{4\pi r^2}

Put the value into the formula

1=\dfrac{87}{4\pi r^2}

r=\sqrt{\dfrac{87}{4\pi}}

r=2.63\ m

Hence, The distance is 2.63 m

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38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari
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P_{1} = P_{2}

\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }

\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }

V_{2} = \frac{T_{2} V_{1} }{T_{1} }

Replacing : T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}

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P_{2} V_{2}  = P_{3} V_{3}

P_{3} = \frac{P_{2} V_{2}}{V_{3}}

P_{3} = 1,317 * 10^{10} Pa

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