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raketka [301]
3 years ago
8

Pls help I need the answers for this

Physics
1 answer:
Nataly [62]3 years ago
8 0

Answer:

<h2><em>See</em><em> </em><em>the</em><em> </em><em>attachment</em></h2><h2><em>Hope</em><em> </em><em>it</em><em> helps</em><em>.</em><em>.</em></h2>

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Consider two displacements, one of magnitude 3 m and another of magnitude 4 m. Show how the displacement vectors may be combined
Rufina [12.5K]

Answer:

Explanation:

A = 3m

B = 4 m

let the angle between the two vectors is θ.

the resultant of two vectors is given by

R=\sqrt{A^{2}+B^{2}+2ABCos\theta }

(a) R = 7 m

So, 7=\sqrt{3^{2}+4^{2}+2\times 3\times 4 Cos\theta }

49 = 9 + 16 + 24 Cosθ

Cosθ = 1

θ = 0°

Thus, the two vectors are inclined at 0°.

(b) R = 1 m

So, 1=\sqrt{3^{2}+4^{2}+2\times 3\times 4 Cos\theta }

1 = 9 + 16 + 24 Cosθ

Cosθ = - 1

θ = 180°

Thus, the two vectors are inclined at 180°.

(c) R = 5 m

So, 5=\sqrt{3^{2}+4^{2}+2\times 3\times 4 Cos\theta }

25 = 9 + 16 + 24 Cosθ

Cosθ = 0

θ = 90°

Thus, the two vectors are inclined at 90°.

3 0
3 years ago
Net force of 200 newtons is applied to a wagon for 3 seconds
AveGali [126]

Momentum of the wagon increases by (200 x 3)

                                                     = 600 newton-sec

                                                     = 600 kg-m/sec
 
6 0
4 years ago
1. Amplitude, loudness, volume, dynamics, and intensity are related but distinct terms. How are they different?
kupik [55]
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
7 0
3 years ago
An airplane is flying in air with a density of 1.29 kg/m3. A pressure gauge measures
jeka57 [31]

Answer:

341 m/s

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

The velocity of the air at the nose is 0 m/s, so:

P₁ = P₂ + ½ ρ v₂²

ΔP = ½ ρ v₂²

Plugging in values:

75000 Pa = ½ (1.29 kg/m³) v²

v = 341 m/s

5 0
3 years ago
A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences
Zanzabum

Answer:

1.79 T

Explanation:

Applying,

F = BILsin∅................ Equation 1

Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force

make B the subject of the equation

B = F/ILsin∅............. Equation 2

From the question,

Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)

Substitute these values into equation 2

B = 2.15/(30×0.04×sin90°)

B = 2.15/1.2

B = 1.79 T

Hence the average field strength is 1.79 T

8 0
3 years ago
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