Answer:
// program in Python to check perfect number
#function to find number is perfect or not
def is_Perfect_Number(n):
#total variable
tot = 1
i = 2
#sum of all divisor of number
while i*i<=n:
if n%i==0:
tot = tot + i + n/i
if tot == n and n != 1:
return 1
i = i+1
return 0
#read until user enter a perfect number
while True:
#read integer
num = int(input("Input an integer: "))
#call the function
if(is_Perfect_Number(num)):
print(num,"is perfect number")
#if perfect number break
break
else:
print(num,"is not a perfect number")
#ask again
print("try again.")
Explanation:
Read number from user and then call the function is_Perfect_Number() with parameter "num".This will find the sum of all divisor of number.If sum is equal to number then it will return 1 else return 0.If the number is not perfect then it will again ask to enter a number until user enter a perfect number.
Output:
Input an integer: 24
24 is not a perfect number
try again.
Input an integer: 28
28 is perfect number
The algorithm is as follows:
1. Start
2. bottles = 0
3. While bottles != 500
3.1 Create bottle
3.2 bottle = bottle + 1
4. Switch off machine
5. Stop
Explanation:
This begins the algorithm
1. Start
This initializes bottles to 0
2. bottles = 0
The loop is repeated until 500 bottles is created
3. While bottles != 500
This creates a new bottle
3.1 Create bottle
This increments the number of bottles by 1
3.2 bottle = bottle + 1
This switches of the machine after all bottles are created
4. Switch off machine
End algorithm
5. Stop
THANKS
Answer:
if(x>12 || x<34)
Explanation:
Mashing the two together using the or '||' operator would allow to run both necessary functions for the next code.
