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kifflom [539]
2 years ago
5

PLS HELP STOICHIOMETRY/CHEM!!!

Chemistry
1 answer:
Mariulka [41]2 years ago
7 0

The molecular formula of the compound that we are required to find is the compound C4H8O8

<h3>What is empirical formula?</h3>

The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.

Carbon -  48.38 g/12   Hydrogen - 6.74 g/1    Oxygen -  53.5 g/16

Carbon - 4                    Hydrogen - 6.74         Oxygen -  8.9

Dividing through by the lowest ratio;

Carbon - 4/4            Hydrogen -  6.74/4           Oxygen 8.9/4

Carbon   1               Hydrogen    2                     Oxygen  2

The empirical formula is CH2O2.

To obtain the molecular formula; brainly.com/question/11588623

[12 + 2 + 32]n = 180

n = 180/[12 + 2 + 32]

n =4

The compound C4H8O8

Learn more about empirical formula:

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<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

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