Answer:
Gamma range
Explanation:
A very intense start is a bright star at very high temperature. Now, hotter the object shorter is the wavelength of peak radiation. The increasing order of wavelength of the given regions in the electromagnetic spectrum are:
gamma range < ultra violet < visible < infrared
Ideally, since the shortest wavelength based on the given options is the gamma range, the peak intensity can also be expected to fall at that wavelength. If the star spectrum was recorded in the UV-visible range of the EM spectrum, then it would fall in the UV range
Explanation:
a) Cr is <u>acid</u> K is <u>base</u>
b) Ca is <u>base</u> and the other left part is <u>acid</u>
c)Ca is <u>base</u> and F2 is <u>acid</u>
<u>d</u><u>)</u><u> </u>NH4 is <u>acid</u> and SO4 is <u>base</u>
Explanation:
Given that,
The frequency of electromagnetic spectrum is 
(A) Let the wavelength of this radiation is 
. We know that,
So, the wavelength of this radiation is 
.
(B) Let E is the energy associated with this radiation. Energy of an electromagnetic radiation is given by :
h is Planck's constant
1 kcal = 4184 J
It means,
Hence, this is the required solution.
Heat is energy, and that energy would eventually cause the object to undergo a phase change.
