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allochka39001 [22]
3 years ago
8

PLZZZ HELP ME!!!!! Complete the table for the function f(x) = 2x - 3

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:


Step-by-step explanation:

f(x) = 2x - 3

f(-2) = 2(-2) -3 = -4 - 3 = -7

f(-1) = 2(-1) -3 = -2 - 3 = - 5

f(0) = 2(0) -3 = 0 - 3 = -3

f(1) = 2(1) -3 = 2 - 3 = -1

f(2) = 2(2) -3 = 4 - 3 = 1

f(3) = 2(3) -3 = 6 - 3 = 3

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-2 - 8i

Step-by-step explanation:

To find the conjugate of a complex number, change the sign of the imaginary part.

The conjugate of -2 + 8i is -2 - 8i.

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One hundred ninety-two students were surveyed about their favorite kind of TV programs. The results are shown in the table. Whic
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A box plot is also known as a(n) box-and-whisker plot. Use the box plot below to find each of the following.
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3 years ago
Please answer this question! 20 points and brainliest!
azamat

Step-by-step explanation:

You have to substitute... 0, 5, & 10, & 3

y = 2x + 3

y = 2(0) + 3

y = 0 + 3

y = 3

(0,3)

y = 2x + 3

y = 2(5) + 3

y = 10 + 3

y = 13

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5 0
3 years ago
Describe the graph of the function.y = |x – 4| – 7
juin [17]
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:

(x-4)=0 ===> x=4,

so that now you have to plot 2 functions!

For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:

|x-4| = -(x-4)=4-x
Then:

for x<=4, y = -x+4-7 = -x-3

for x=>4, (x-4) is positive, so no changes:

y= x-4-7 = x-11,

Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11

In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:

x=4 and x= 3 for y=-x-3

And just x=5 for y=x-11

The reason is that the absolute value is continuous, so x=4 works for both:

x=4===> y=-4-3 = -7

x==4 ====> y = 4-11=-7!

abs() usually have a cusp int he point where it is =0

Hope it helps, despite being this long!
3 0
3 years ago
Read 2 more answers
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