The answer is 2.3. I just answered this question and got it right.
Answer:
Impulse = 48 kg m/s
Gain in momentum = 48 kg m/s
Explanation:
Force (F) = 6N
Time (t) = 8
Mass (m) = 3 kg
Final velocity (v) = ?
Initial velocity (u) = 0 m/s
First, find acceleration
F = m * a
a = F / m
a = 6 / 3
a = 2 m/s^2
Now, find final velocity
v = u + a * t
v = 0 + 2 * 8
v = 16 m/s
Now, find impulse
Impulse = change in momentum
Impulse = final momentum - initial momentum
Impulse = m * v - m * u
Impulse = m ( v - u )
Impulse = 3 ( 16 - 0 )
Impulse = 48 kg m/s
Here, gain in momentum is same as impulse.
Answer:
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Answer:
2 N/m
Explanation:
Given that
The length of a wire, l = 15 m
Force on the wire, F = 60 N
Surface tension on the liquid, S = ?
The formula to solve this problem is given as
F = S * 2 L, where
F = force on the liquid
S = surface tension of the liquid
L= length of the wire
On substituting the values of each, we have
60 = S * (2 * 15)
S = 60 / 30
S = 2 N/m
Thus, we can say then, that the surface tension of the liquid is 2 N/m