A force that pulls on mass to another
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vo = 25 m/sec
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
Answer:
The number of fission are equal to 1.947 x 10¹⁶
Explanation:
Energy of one fission=208*1.6*10⁻¹³ Joule.
Power of the bulb=120 Watts.
Time t in seconds = 1.5h=5400 seconds
Total energy E=Power* time=120*5400=64.8 x 10⁴ Joule.
Number of fissions N= total energy / energy for one fission
=(64.8 x 10⁴)/(208x1.6x10⁻¹³)
=1.947 x 10¹⁶
Answer:
255 [m].
Explanation:
1) the formula is (d - requred distance, V₀ - initial velocity, t - elapsed time, a - deceleration):
![d=V_0t+\frac{at^2}{2};](https://tex.z-dn.net/?f=d%3DV_0t%2B%5Cfrac%7Bat%5E2%7D%7B2%7D%3B)
2) according to the formula above the required distance is:
d=10*30-0.5*0.1*900=300-45=255 [m].
The final velocity of the 15 kg mass is 18.33 m/s.
<h3>
Conservation of linear momentum</h3>
The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;
![m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\](https://tex.z-dn.net/?f=m_1%20u_1%20%2B%20m_2%20u_2%20%3D%20m_1%20v_1%20%2B%20m_2%20v_2%5C%5C%5C%5C)
Where;
- m₁ is the mass of the first object = 25 kg
- u₁ is the initial velocity of the first object = 15 m/s
- m₂ is the mass of the second object = 15 kg
- u₂ is the initial velocity of the second object = -10 m/s
- v₁ is the final velocity of the first object = -2 m/s
- v₂ is the final velocity of the second object
Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238