1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fgiga [73]
3 years ago
10

A ball is thrown downward at 4.5 m/s and accelerates at 9.8 m/s^2. What is its instantaneous velocity 2.4 s later?​

Physics
1 answer:
Alex3 years ago
8 0

Answer:

87

Explanation:

You might be interested in
Which one of the following is not equivalent to 2.50 miles?
lisabon 2012 [21]

Answer:

Choice C is not equivalent to 2.50 miles.

Explanation:

The given data is now converted into feet, inches, kilometers, yards and centimeters:

mi - ft

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)

x = 13200\,ft

x = 1.320\times 10^{4}\,ft (Choice A)

mi - in

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)\cdot \left(12\,\frac{in}{ft} \right)

x = 158400\,in

x = 1.584\times 10^{5} (Choice B)

mi - km

x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)

x = 4.025\,km (Different from Choice C)

mi - yd

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi}\right) \cdot \left(\frac{1}{3}\,\frac{yd}{ft}  \right)

x = 4400\,yd

x = 4.40\times 10^{3}\,yd (Choice D)

mi - cm

x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)\cdot \left(100000\,\frac{cm}{km}\right)

x = 402500\,cm

x = 4.025\times 10^{5}\,cm (Choice E)

Choice C is not equivalent to 2.50 miles.

6 0
4 years ago
Solve for x. 4(x+1)≤4x+3
alexdok [17]
4x + 4 < 4x + 3 (expand it)
4 < 3 (cancel 4x on both sides)
Since 4 < 3 is not true there is no solution.

Answer: NO SOLUTION.
3 0
3 years ago
Read 2 more answers
There are four charges, each with a magnitude of 4.25 C. Two are positive and two are negative. The charges are fixed to the cor
VMariaS [17]

Answer:

 F = 7.68 10¹¹ N,  θ = 45º

Explanation:

In this exercise we ask for the net electric force. Let's start by writing the configuration of the charges, the charges of the same sign must be on the diagonal of the cube so that the net force is directed towards the interior of the cube, see in the attached numbering and sign of the charges

The net force is

          F_ {net} = F₂₁ + F₂₃ + F₂₄

bold letters indicate vectors. The easiest method to solve this exercise is by using the components of each force.

let's use trigonometry

          cos 45 = F₂₄ₓ / F₂₄

          sin 45 = F_{24y) / F₂₄

          F₂₄ₓ = F₂₄ cos 45

          F_{24y} = F₂₄ sin 45

let's do the sum on each axis

X axis

          Fₓ = -F₂₁ + F₂₄ₓ

          Fₓ = -F₂₁₁ + F₂₄ cos 45

Y axis  

         F_y = - F₂₃ + F_{24y}

         F_y = -F₂₃ + F₂₄ sin 45

They indicate that the magnitude of all charges is the same, therefore

         F₂₁ = F₂₃

Let's use Coulomb's law

         F₂₁ = k q₁ q₂ / r₁₂²

       

the distance between the two charges is

         r = a

         F₂₁ = k q² / a²

we calculate F₂₄

           F₂₄ = k q₂ q₄ / r₂₄²

the distance is

           r² = a² + a²

           r² = 2 a²

         

we substitute

           F₂₄ = k  q² / 2 a²

we substitute in the components of the forces

          Fx = - k \frac{q^2}{a^2} +  k \frac{q^2}{2 a^2}  \ cos 45

          Fx = k \frac{q^2}{a^2}  ( -1 + ½ cos 45)

          F_y = k \frac{q^2}{a^2} ( -1 +  ½ sin 45)    

         

We calculate

            F₀ = 9 10⁹ 4.25² / 0.440²

            F₀ = 8.40 10¹¹ N

       

            Fₓ = 8.40 10¹¹ (½ 0.707 - 1)

            Fₓ = -5.43 10¹¹ N

         

remember cos 45 = sin 45

             F_y = - 5.43 10¹¹  N

We can give the resultant force in two ways

a) F = Fₓ î + F_y ^j

          F = -5.43 10¹¹ (i + j)   N

b) In the form of module and angle.

For the module we use the Pythagorean theorem

          F = \sqrt{F_x^2 + F_y^2}

          F = 5.43 10¹¹  √2

          F = 7.68 10¹¹ N

in angle is

           θ = 45º

7 0
3 years ago
An empty beaker is placed on a top-pan balance. Some water is now poured into the beaker.What is the weight of the water? A. 0.0
mario62 [17]

Answer:

A. 0.044 kg

Explanation:

We need to subtract the sum of (beaker+water - empty beaker) which is 0.106 kg - 0.062 kg = 0.044 kg. The answer will not be written in Newton because this unit is used for force only and in this question w have to find the weight.

Hope it is enough.

Please mark me as brainliest.

6 0
3 years ago
Can A positively charged body attract another positively charged body​
andriy [413]

Like charges repel, unlike charges attract

Two protons will also tend to repel each other because they both have a positive charge. On the other hand, electrons and protons will be attracted to each other because of their unlike charges.

So I would say no, unless the two bodies are placed close to each other where one has much more charge than the other, then due to induction, force of attraction becomes more than the force of repulsion.

3 0
3 years ago
Other questions:
  • А<br> is a push or pull.
    12·1 answer
  • 4. A solution that contains a large amount of salt and a small amount of water is said to be a _______ solution.
    15·1 answer
  • Which statement about a pair of units is true? A yard is shorter than a meter. Amile is shorter than a kilometer. A foot is shor
    12·1 answer
  • A cat is sleeping on the dashboard of a moving car. Imagine that the cat does not wake up and is not touched by anything. Use Ne
    5·1 answer
  • Because she had serious traffic accident on Friday the 13th of last month, Felicia is conceived that all Friday the 13th will br
    14·1 answer
  • The size of the electrical potential is measured in
    9·1 answer
  • Alkali metals _____.
    10·1 answer
  • Thanks+ BRAINLIST only for correct answers
    15·2 answers
  • What type of lens is a flat lens?
    8·2 answers
  • A spaceprobe in outer space is flying with a constant speed of 1.795 km/s. The probe has a payload of 1635.0 kg and it carries 4
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!