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diamong [38]
3 years ago
5

A 15m long wire is placed horizontally on the surface of a liquid and is gently pulled up with the force of 60N to keep the wire

in equilibrium.what is the surface tension of the liquid?​
Physics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

2 N/m

Explanation:

Given that

The length of a wire, l = 15 m

Force on the wire, F = 60 N

Surface tension on the liquid, S = ?

The formula to solve this problem is given as

F = S * 2 L, where

F = force on the liquid

S = surface tension of the liquid

L= length of the wire

On substituting the values of each, we have

60 = S * (2 * 15)

S = 60 / 30

S = 2 N/m

Thus, we can say then, that the surface tension of the liquid is 2 N/m

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liubo4ka [24]

The statement that is a quantitative observation is that bird has four different colors on it (option B).

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A quantitative observation has to do with numbers or numeric analysis.

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8 0
1 year ago
Juan measured the temperature of salt water. He then added 273 to the measured value. Which conversion is Juan most likely doing
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7 0
3 years ago
Model rocket A is launched at an angle of 70° above the x axis, with an initial velocity of 40 m/s. An identical rocket B is lau
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<span>A. Rocket A will travel farther horizontally than rocket B.

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3 0
3 years ago
The 6 strings on a guitar all have about the same length and are stretched with about the same tension.The highest string vibrat
ahrayia [7]

Answer:

B. d(low)=4d(high)

Explanation:

Frequency of a string can be written as;

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Where;

v = sound velocity

L = string length

Frequency can be further expanded to;

f = v/2L = (1/2L)√(T/u) ......1

Where;

m= mass,

u = linear density of string,

T = tension

p = density of string material

A = cross sectional area of string

d = string diameter

u = m/L .......2

m = pAL = p(πd^2)L/4 (since Area = (πd^2)/4)

f = (1/2L)√(T/u) = (1/2L)√(T/(m/L))

f = (1/2L)√(T/((p(πd^2)L/4)/L))

f = (1/2L)√(4T/pπd^2)

f = (1/L)(1/d)√(4T/pπ)

Since the length of the strings are the same, the frequency is inversely proportional to the string diameter.

f ~ 1/d

So, if

4f(low) = f(high)

Then,

d(low) = 4d(high)

6 0
3 years ago
A box moves 5\,\text m5m5, start text, m, end text horizontally when a force, F =10\,\text NF=10NF, equals, 10, start text, N, e
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Answer:

??

Explanation:

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3 years ago
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