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SOVA2 [1]
3 years ago
5

Light travels at 3.0 × 108 m/s in a vacuum. Use the index of refraction for water to determine the speed of light in water. Roun

d your answer to the nearest tenth.
Physics
2 answers:
rusak2 [61]3 years ago
5 0
The answer is 2.3. I just answered this question and got it right.
sp2606 [1]3 years ago
3 0

<u>Answer:</u> The velocity of light in water is 225056264.1 m/s.

<u>Explanation:</u>

To calculate the speed of light in medium (water), we use the formula:

\eta=\frac{c}{v}

where,

\eta = index of refraction of water = 1.333

c = speed of light in vacuum = 3\times 10^8m/s

v = speed of light in water = ?m/s

Putting values in above equation, we get:

1.333=\frac{3\times 10^8}{v}\\\\v=2.2505626406\times 10^8m/s

To round the speed of light in water to the nearest tenth place, we will multiply the exponent with the answer and then round off the tenth place.

2.2505626406\times 10^8=225056264.06

Rounding 0.06 to 1 because 6 is more than 5, we get:

\Rightarrow 225056264.1m/s

Hence, the velocity of light in water is 225056264.1 m/s.

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The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

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