Answer:
Part a)

Part b)

Explanation:
Part a)
As we know that electric field intensity due to some given charge distribution is given as

now electric flux through a spherical surface of radius r is given as


now by Guass law we know that


now volume charge density is given as


Part b)
Total charge inside the radius R is given as

distance = 10km
time = 1 1/2 = 3/2 hours
speed = distance/time = 10 / 3/2 = 20/3 = 6.67 Km/h
Answer:
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Explanation:
Given:
Speed of sound in air = 320 m/s
Speed of sound in water = 1600 m/s
Time taken to reach certain distance in air = 2.5 sec
a.
We have to find the distance traveled by sound in air.
Distance = Product of speed and time.
⇒ 
⇒ 
⇒
meters.
b.
Now we have to find how much time the sound will take to travel in water.
⇒ Time = Ratio of distance and speed
⇒ 
⇒
<em> ...distance = 800 m and speed = 1600 m/s</em>
⇒ 
⇒
seconds.
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Answer:
What will be the increase in frequency if these waves are reflected = 2979.63Hz
Explanation:
The detailed steps and appropriate formula is as shown in the attached file.