I think D. liquid water moving along the surfac
V=IR
V=15x11
V=165ohms
I don’t quite remember the unit
Ohms law
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Answer:
5.03 m/s
Explanation:
Give
Speed = v = 24m/s
Wavelength = λ = 30cm = 0.3m
Amplitude = A = 1.0cm = 0.01m
The velocity of a point in Simple Harmonic Motion
at any time t is given by the following formula
v = ωA cos ωt
The value is the Maximum when cosωt.
The maximum value of cosωt. is 1.
Hence the maximum velocity is ωA
Velocity of the wave v=n λ
n = v/ λ = 24 /0.3 = 80
ω = 2πn = 2π*80 = 502.86 rad/s
Maximum velocity of the particle is
ωA = 502.86 * 0.01 = 5.03m/s
